Limit of e^(2x) / sinh(2x) as x approaches infinity

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SUMMARY

The limit of e^(2x) / sinh(2x) as x approaches infinity is evaluated by transforming the expression into e^(2x) / [(e^(2x) - e^(-2x)) / 2]. This simplification leads to the form (∞) / [(∞ - 0) / 2]. By dividing both the numerator and denominator by e^(2x), the limit can be further analyzed, ultimately confirming that the limit approaches 1 as x approaches infinity.

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Homework Statement



Find the limit of e^(2x) / sinh(2x), as x approaches infinity.


Homework Equations





The Attempt at a Solution



Changed equation to e^(2x) / [(e^(2x) - e^(-2x)) / 2]. Based of the sinh identity.

found limit of e^(2x) = ∞ ... e^(-2x) = 0 ... 2 = 2 ...

New equation ( ∞ ) / [( ∞ - 0 ) / 2]

...

I am unsure how to continue after this.
 
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Hi ccha ! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
ccha said:
… Changed equation to e^(2x) / [(e^(2x) - e^(-2x)) / 2]. Based of the sinh identity.

Now divide top and bottom by e2x

what do you get? :smile:
 

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