Limit of f(x,y) as x^2+y^2→∞: Calculate & Analyze

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Discussion Overview

The discussion revolves around the limit of the function $$f(x,y)=\frac{\ln(1+x^2y^2)}{x^4+y^4}$$ as $$x^2+y^2$$ approaches infinity. Participants explore different methods to analyze the limit, including polar coordinates and L'Hôpital's rule.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests converting to polar form to analyze the limit, proposing that the limit approaches zero as the denominator grows faster than the numerator.
  • Another participant recommends using L'Hôpital's rule, indicating that multiple applications may be necessary to evaluate the limit.
  • A later reply mentions that after applying L'Hôpital's rule, the numerator simplifies to $$24\cos^2(\theta)\sin^2(\theta)$$, while the denominator tends to infinity, suggesting the limit is zero.
  • There is a question about the validity of stating that $$r^2 \to \infty$$ is equivalent to $$r \to \infty$$ when calculating limits, with some participants expressing that it is unusual but not incorrect.
  • An alternative approach is proposed using the upper bound $$\ln(1+u) \le \sqrt{u}$$ to estimate the limit.
  • Participants discuss the number of applications of L'Hôpital's rule needed, with differing opinions on whether four applications are necessary.

Areas of Agreement / Disagreement

Participants express differing views on the methods for evaluating the limit, particularly regarding the application of L'Hôpital's rule and the equivalence of limits as $$r^2$$ and $$r$$ approach infinity. No consensus is reached on the necessity of multiple applications of L'Hôpital's rule.

Contextual Notes

Participants do not fully resolve the mathematical steps involved in applying L'Hôpital's rule, and there are assumptions about the behavior of the function as $$x^2+y^2$$ approaches infinity that remain unexamined.

Petrus
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$$f(x,y)=\frac{\ln(1+x^2y^2)}{x^4+y^4}$$
decide if it got a limit if $$x^2+y^2=\infty$$. if so calculate it.

well I go to polar form and we got
$$\lim_{r^2->\infty}\frac{\ln(1+r^2\cos^2(\theta)r^2\sin^2( \theta))}{r^4\cos^2(\theta)^4+r^4\sin^4(\theta)}$$
we see both approach to limit but the bottom will go a lot faster so it will be equal to zero, is this wrong to say like this?

Regards,
$$|\pi\rangle$$
 
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Petrus said:
$$f(x,y)=\frac{\ln(1+x^2y^2)}{x^4+y^4}$$
decide if it got a limit if $$x^2+y^2=\infty$$. if so calculate it.

well I go to polar form and we got
$$\lim_{r^2->\infty}\frac{\ln(1+r^2\cos^2(\theta)r^2\sin^2( \theta))}{r^4\cos^2(\theta)^4+r^4\sin^4(\theta)}$$
we see both approach to limit but the bottom will go a lot faster so it will be equal to zero, is this wrong to say like this?

Regards,
$$|\pi\rangle$$

Hi Petrus, :)

I would use the L'Hopital's rule over the variable \(r\).
 
Sudharaka said:
Hi Petrus, :)

I would use the L'Hopital's rule over the variable \(r\).
Thanks! Now I see without finish the L'Hopital's rule as you need to do it 4 times :P we will end with a $$24\cos^2(\theta)sin^2(\theta)$$ at top and we will keep have some r at bottom which will make bottom to $$\infty$$ so it will equal to 0!:) I got one question that I would like to know.

is it allowed to say $$r^2->\infty$$ is same as $$r->\infty$$ when you calculate limits?

Regards,
$$|\pi\rangle$$
 
Petrus said:
Thanks! Now I see without finish the L'Hopital's rule as you need to do it 4 times :P we will end with a $$24\cos^2(\theta)sin^2(\theta)$$ at top and we will keep have some r at bottom which will make bottom to $$\infty$$ so it will equal to 0!:) I got one question that I would like to know.

Alternatively, you can use the upper bound $\ln(1+u) \le \sqrt u$.

Btw, do you need 4 applications of l'Hospital's rule? It seems I only need 1.

is it allowed to say $$r^2->\infty$$ is same as $$r->\infty$$ when you calculate limits?

It's unusual, but I don't think it's wrong.
It fits into the definition of a limit.
 
I like Serena said:
Alternatively, you can use the upper estimate $\ln(1+u) \le \sqrt u$.

Btw, do you need 4 applications of l'Hospital's rule? It seems I only need 1.
It's unusual, but I don't think it's wrong.
It fits into the definition of a limit.
you are correct! we will be able to divide $$4r^3$$ on top and bottom! Thanks!

Regards,
$$|\pi\rangle$$
 

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