Limit of sin2x/sin3x | Find the Solution

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Homework Help Overview

The problem involves determining the limit of the expression \(\lim_{x \to 0} \frac{\sin 2x}{\sin 3x}\), which falls under the subject area of calculus, specifically limits and trigonometric functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the hint provided, which suggests using known limits involving \(\sin x\). Some express confusion about how to apply the hint to the specific limit in question. Others point out the relevance of the limit \(\lim_{x \to 0} \frac{\sin x}{x}\) and its connection to the problem.

Discussion Status

The discussion has seen participants questioning the relationship between the hint and the limit they are trying to evaluate. Some have indicated a breakthrough in understanding after receiving guidance, while others are still exploring the connections between the limits involved.

Contextual Notes

There is a mention of a common limit \(\lim_{x \to 0} \frac{\sin x}{x} = 1\), which is relevant to the problem but not the direct focus. Participants are navigating through their understanding of the hint and its application to the specific limit.

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Homework Statement



Determine the limit of

[itex]\lim_{x \to 0} \frac {sin2x}{sin3x}[/itex]

Homework Equations



Hint: Find [itex]\lim_{x\to 0} (\frac{2 sin 2x}{2x}) (\frac{3x}{3 sin 3x})[/itex]

The Attempt at a Solution



I've been blankly staring at it not knowing where to start. I think the only thing that the hint manages to do is to confuse me.

Any help on helping me to start it? I don't understand the hint.

Thanks in advance.
 
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Do you not what is [tex]\lim _{x \to 0} \frac{sin(x)}{x}[/tex]?

ehild
 
In your book or notes, you should find how to evaluate
[tex]\lim_{x \to 0} \frac{\sin x}{x}[/tex]
 
ehild said:
Do you not what is [tex]\lim _{x \to 0} \frac{sin(x)}{x}[/tex]?

ehild

Yes they are equal to one, but they aren't asking for [tex]\lim_{x \to 0} \frac {sinx}{x}[/tex]

They are asking for [tex]\lim_ {x \to 0} \frac{sin2x}{sin3x}[/tex]
 
And you see absolutely no connection to that limit and the hint?
 
vela said:
And you see absolutely no connection to that limit and the hint?

Ohhhhhh !

Its funny how someone can say so little yet help so much hehe. Thanks, I got it now.
 
Answer is 2/3.
 
Nano-Passion said:
Its funny how someone can say so little yet help so much hehe. Thanks, I got it now.
I think we've all had those moments where we fail to see what in hindsight seems so obvious. :wink:
 
vela said:
I think we've all had those moments where we fail to see what in hindsight seems so obvious. :wink:

Thank you for your help by the way:)
 
  • #10
For a more "formal" look, let u= 2x so that you have
[tex]\lim_{x\to 0}\frac{sin(2x)}{2x}= \lim_{u\to 0}\frac{sin(u)}{u}[/tex]
 
  • #11
HallsofIvy said:
For a more "formal" look, let u= 2x so that you have
[tex]\lim_{x\to 0}\frac{sin(2x)}{2x}= \lim_{u\to 0}\frac{sin(u)}{u}[/tex]

Hey halls, thanks for the suggestion. Will keep in mind in the future. ^.^
 

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