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## Homework Statement

I wish to obtain the Thevenin equivalent for the network show in the attachment between the terminals a and b.

**2. The attempt at a solution**

First I considered the voltage source alone (replaced current source by an open circuit).

[tex] I = \frac{V}{Z_T} = \nfrac{20}{5+10+j5+j10+ (2*j4)} = 0.728A \angle-56.89\degrees [/tex]

[tex] \therefore V_{AB}^1 = (0.728A\angle-56.89\degrees) * (5+10+j5+j4) = 12.74V\angle-25.92\degrees [/tex]

Then I considered the current source alone (replaced the voltage source by a short):

Current through upper branch = [tex] \frac { 2A\angle90\degrees (10 + j5 + j10 - j4 + (2*j4))||5}{10+j5+j10-j4+ (2*j4)} = 0.282A\angle29.83\degrees [/tex]

[tex] \therefore V_{AB}^2 = (0.282\angle29.83\degrees)(j10 -j4 + j4) = 2.82V\angle119.83\degrees [/tex]

[tex] V_{AB} = V_{AB}^1 + V_{AB}^2 = 10.529V\angle-17.25\degrees [/tex]

Can someone please check this for me? I'm not sure whether I did some mistake and I need to know whether I understood these.

Thank you for your time,

Lunat1c