Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Limit supreme solve i am not able to

  1. Sep 16, 2007 #1
    limit supreme...plz solve i am not able to

    [tex]\limsup{t\rightarrow {\infty}} \int{p(s)ds} >1[/tex]
    and limit of integral are [tex]t-\tau[/tex] to [tex]t[/tex] where
    [tex]\tau[/tex]>0



    plz solve i am not able to
     
  2. jcsd
  3. Sep 16, 2007 #2
    please ane body help me
     
  4. Sep 16, 2007 #3

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    It bothers you that someone did not answer in 4 minutes. We are not payed to sit at computers waiting to answer questions you know!

    In any case, what exactly is your question? Obviously the limit will depend on exactly what p(t) is!
     
  5. Sep 17, 2007 #4
    sorry bt the quetion was given exactly asit is to me as an assignment
     
  6. Sep 17, 2007 #5
    For what class?
     
  7. Sep 18, 2007 #6
    for maths class, i am in an technical college 2nd year
     
  8. Sep 18, 2007 #7
    plz help me
     
  9. Sep 18, 2007 #8

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    There is no help we can give without knowing p! For example,
    [tex]\int_{t-\tau}^t \frac{1}{t}dt= ln(t)-ln(t-\tau)= ln\left(\frac{t}{t-\tau}\right)= ln\right(\frac{1}{1-\frac{\tau}{t}}\right)[/tex]
    which has limit ln(1)= 0 as t goes to infinity but
    [tex]\int_{t-\tau}^t t dt= \frac{1}{2}(t^2- (t-\tau)^2= \frac{1}{2}(-2t\tau +\tau^2)[/tex]
    which has no limit as t goes to infinity.
     
  10. Sep 21, 2007 #9
    thanx for the help
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Limit supreme solve i am not able to
Loading...