Limit supreme solve i am not able to

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Discussion Overview

The discussion centers around the mathematical problem involving the limit superior of an integral, specifically the expression \(\limsup_{t\rightarrow {\infty}} \int_{t-\tau}^{t} p(s) ds > 1\) where \(\tau > 0\). Participants seek assistance in solving this problem, which appears to be part of a mathematics assignment.

Discussion Character

  • Homework-related, Mathematical reasoning, Exploratory

Main Points Raised

  • One participant requests help with the limit superior of an integral involving an unspecified function \(p(s)\).
  • Another participant emphasizes that the limit will depend on the specific form of \(p(t)\), indicating that without this information, no assistance can be provided.
  • A participant provides examples of integrals with different functions, showing how they behave as \(t\) approaches infinity, but does not conclude which function \(p(s)\) might be.
  • Participants express frustration regarding the lack of immediate responses and clarify that they are not obligated to provide quick answers.
  • There is a mention of the context of the problem being an assignment for a second-year technical college mathematics class.

Areas of Agreement / Disagreement

Participants generally agree that the solution to the problem is contingent upon knowing the function \(p(s)\). However, there is no consensus on what \(p(s)\) might be or how to approach the problem without that information.

Contextual Notes

The discussion highlights the importance of the function \(p(s)\) in determining the behavior of the integral, but does not resolve what \(p(s)\) is or provide a complete solution to the problem.

Who May Find This Useful

Students or individuals studying calculus or mathematical analysis, particularly those interested in limit superior and integral calculus.

rishikesh86
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limit supreme...please solve i am not able to

[tex]\limsup{t\rightarrow {\infty}} \int{p(s)ds} >1[/tex]
and limit of integral are [tex]t-\tau[/tex] to [tex]t[/tex] where
[tex]\tau[/tex]>0



please solve i am not able to
 
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please ane body help me
 
rishikesh86 said:
[tex]\limsup{t\rightarrow {\infty}} \int{p(s)ds} >1[/tex]
and limit of integral are [tex]t-\tau[/tex] to [tex]t[/tex] where
[tex]\tau[/tex]>0



please solve i am not able to

It bothers you that someone did not answer in 4 minutes. We are not payed to sit at computers waiting to answer questions you know!

In any case, what exactly is your question? Obviously the limit will depend on exactly what p(t) is!
 
sorry bt the quetion was given exactly asit is to me as an assignment
 
For what class?
 
for maths class, i am in an technical college 2nd year
 
please help me
 
There is no help we can give without knowing p! For example,
[tex]\int_{t-\tau}^t \frac{1}{t}dt= ln(t)-ln(t-\tau)= ln\left(\frac{t}{t-\tau}\right)= ln\right(\frac{1}{1-\frac{\tau}{t}}\right)[/tex]
which has limit ln(1)= 0 as t goes to infinity but
[tex]\int_{t-\tau}^t t dt= \frac{1}{2}(t^2- (t-\tau)^2= \frac{1}{2}(-2t\tau +\tau^2)[/tex]
which has no limit as t goes to infinity.
 
thanx for the help
 

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