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[tex]\frac{lim}{h\rightarrow0}[/tex] [tex]\frac{\sqrt{1+h}-1}{h}[/tex]

I don't know if the way I approached the question is right, I'll give you a step by step of what I attempted:

First I converted the square root into 1^{1/2}and h^{1/2}(can I do that? Is that correct?)

Then I continued to evaluate, getting h^{1/2}over h

Finally I determined the value to be 0 because 0^{-1/2}is 0.

I feel as though my first step is where I might have errored but I'm not sure how else to approach it, perhaps by converting the h to a h^{-1}

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# LIMITS, complicated square roots and factoring

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