Limits of functions with negative exponents

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SUMMARY

The limit of the function as h approaches 0 for the expression lim h->0 [(11+h)^-1 - 11^-1]/h evaluates to 121. The initial approach involved rewriting the numerator into two fractions with a common denominator of h. However, a sign error was identified in the calculations, which necessitates a review of the algebraic manipulations performed. Correcting this error is essential for accurate results in limit evaluations involving negative exponents.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with negative exponents
  • Basic algebraic manipulation skills
  • Knowledge of L'Hôpital's Rule for indeterminate forms
NEXT STEPS
  • Review the concept of limits and continuity in calculus
  • Study the properties and applications of negative exponents
  • Practice problems involving L'Hôpital's Rule for limits
  • Explore advanced limit techniques, including Taylor series expansions
USEFUL FOR

Students studying calculus, particularly those focusing on limits and derivatives, as well as educators seeking to clarify concepts related to negative exponents and limit evaluations.

alexk307
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Homework Statement



lim h->0 [(11+h)^-1 - 11^-1]/h

Homework Equations





The Attempt at a Solution



I made the numerator into two fractions with the denominator h. After combining the fractions in the numerator I was left with 121 when I put in 0 for h.
 
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alexk307 said:

Homework Statement



lim h->0 [(11+h)^-1 - 11^-1]/h

Homework Equations





The Attempt at a Solution



I made the numerator into two fractions with the denominator h. After combining the fractions in the numerator I was left with 121 when I put in 0 for h.

You have a sign error. Check your work.
 

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