Limits of the Path Length of B-field induced gyroradius

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SUMMARY

This discussion focuses on deriving the path length of a charged particle in a magnetic field (B-field) using the equations for a helix and gyroradius. The helix is defined as [a*cos(t), a*cos(t), b*t] with a path length of P = \sqrt{(a^2 + b^2)} and gyroradius given by r = \frac{v_{perp} m^*}{qB}. The user encounters issues with boundary conditions, particularly at zero and infinite magnetic fields, leading to confusion about the applicability of the gyroradius in these scenarios. The discussion highlights the need for clarity on the behavior of the path length under extreme field conditions.

PREREQUISITES
  • Understanding of classical mechanics, specifically the motion of charged particles in magnetic fields.
  • Familiarity with the mathematical representation of helices and parametric equations.
  • Knowledge of the concepts of gyroradius and its dependence on velocity, mass, charge, and magnetic field strength.
  • Basic grasp of boundary conditions in physics and their implications on mathematical models.
NEXT STEPS
  • Research the mathematical derivation of path lengths for charged particles in varying magnetic field strengths.
  • Study the implications of boundary conditions on the motion of charged particles in electromagnetic fields.
  • Examine the behavior of gyroradius as the magnetic field approaches zero and its physical significance.
  • Explore advanced topics in plasma physics related to particle motion in magnetic confinement systems.
USEFUL FOR

This discussion is beneficial for physicists, particularly those specializing in electromagnetism and plasma physics, as well as students and researchers exploring the dynamics of charged particles in magnetic fields.

thefireman
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Hi,
I am trying to derive the path length of a charged particle in a B-field. I am assuming the particle will travel a distance L along the applied field. Using the following equations for the path length of a helix and gyroradius:
Helix defined as
[a*cos(t),a*cos(t),b*t]for t on [0,T] has a path length of
P=\sqrt{(a^2+b^2)}
r=\frac{v_{perp}m^*}{qB}
and assuming that bt must equal L at T=1 (parametrize helix from 0 to 1), I get the following expression:

P=\sqrt{(\frac{v_{perp}m^*}{qB})^2+L^2}

However, the bounds do not make sense. At zero field, It should simply travel in a straight line, i.e. P=L.
I am not sure about the "infinite" field, since it is oscillating more rapidly but with an ever decreasing radius. I could argue that the radius being 0 means only the vertical distance is traveled, or that it just rotates infinity at 0 radius?
In either case, I cannot get the BC for B=0, as this causes the expression to be infinite.

Can I simply not apply the gyroradius in a zero field condition, or did I derive this incorrectly? What is the limiting case of infinite field? Actually quite an interesting problem!
 
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