Line Integral Homework: Find Curve & Vector Field for Green's Theorem [Solved]

Click For Summary
SUMMARY

The discussion focuses on applying Green's Theorem to find a parameterized curve and a vector field that satisfy the equation \(\int\gamma F \, ds = \int\int 2xy \, dx \, dy\). The parameterized curve \(\gamma\) is identified as a circle centered at (1,0) with a radius of 2, parametrized by \(x = 1 + 2\cos(t)\) and \(y = 2\sin(t)\). The vector field \(F\) is initially defined as \(F = (xy^2, 2x^2y)\), with the conclusion that there are infinitely many possible vector fields that can satisfy the theorem, allowing for modifications using differentiable functions.

PREREQUISITES
  • Understanding of Green's Theorem
  • Knowledge of parameterization of curves
  • Familiarity with vector fields in multivariable calculus
  • Basic skills in calculus and differential equations
NEXT STEPS
  • Study the applications of Green's Theorem in various contexts
  • Learn about parameterization techniques for different geometric shapes
  • Explore the concept of vector fields and their properties
  • Investigate modifications of vector fields using differentiable functions
USEFUL FOR

Students and educators in multivariable calculus, particularly those focusing on vector calculus and the applications of Green's Theorem. Additionally, mathematicians interested in the properties of vector fields will find this discussion beneficial.

mottov2
Messages
13
Reaction score
0

Homework Statement


Find the parameterized curve gamma and vector field F so that
the [itex]\int[/itex][itex]\gamma[/itex] F ds = [itex]\int[/itex][itex]\int2xy dx dy[/itex] by Green's Theorem.
where -2<y<2
1-sqrt(4-y2) < x < 1+sqrt(4-y2)

The Attempt at a Solution

x = 1 + sqrt(4-y2)
(x-1)2=4-y2
(x-1)2+y2=4

so the path is a circle centered at (1,0) with radius of 2.
parametrize this by setting x = 1+2Cos(t) and y = 2Sin(t)

for the vector field I got F = (xy2,2x2y)
but is there more than one possible vector field?
 
Physics news on Phys.org
mottov2 said:

Homework Statement


Find the parameterized curve gamma and vector field F so that
the [itex]\int[/itex][itex]\gamma[/itex] F ds = [itex]\int[/itex][itex]\int2xy dx dy[/itex] by Green's Theorem.
where -2<y<2
1-sqrt(4-y2) < x < 1+sqrt(4-y2)

The Attempt at a Solution




x = 1 + sqrt(4-y2)
(x-1)2=4-y2
(x-1)2+y2=4

so the path is a circle centered at (1,0) with radius of 2.
parametrize this by setting x = 1+2Cos(t) and y = 2Sin(t)

for the vector field I got F = (xy2,2x2y)
but is there more than one possible vector field?

Yes, there are infinitely many such vector fields. For example, you can modify yours like this:$$
\vec F = \langle xy^2+g(x), 2x^2y+h(y)\rangle$$where h and g can be any differentiable functions.
 

Similar threads

Replies
3
Views
2K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
12
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K