Line integral over a Vector Field

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SUMMARY

The discussion centers on calculating the line integral of the vector field F(x,y,z) = (yz + 3x²)i + xzj + xy k from point A = (0,1,3) to point B = (1,2,2). Participants clarify that dl represents the differential path element, which depends on the chosen path for integration. The correct parametrization for the path is r(t) = , leading to a calculated integral value of 5. The discussion highlights the importance of recognizing that the integral's value is path-independent due to the conservative nature of the vector field.

PREREQUISITES
  • Understanding of vector fields and line integrals
  • Familiarity with parametrization of paths in three-dimensional space
  • Knowledge of the Gradient Theorem and its applications
  • Basic calculus concepts, including integration techniques
NEXT STEPS
  • Study the Gradient Theorem and its implications for line integrals
  • Learn about conservative vector fields and their properties
  • Explore different parametrization techniques for complex paths
  • Practice solving line integrals with varying vector fields and paths
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Students in calculus or vector calculus courses, mathematicians interested in line integrals, and anyone seeking to deepen their understanding of vector fields and their applications in physics and engineering.

Smazmbazm
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Homework Statement



Given a vector field

F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}

Calculate the line integral

∫_{A}^{B}F\bullet dl

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz ?

Thanks for any assistance.
 
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Smazmbazm said:

Homework Statement



Given a vector field

F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}

Calculate the line integral

∫_{A}^{B}F\bullet dl

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz ?

Thanks for any assistance.

No, dl isn't equal to (dx,dy,dz) in general. dl depends on the path you are integrating along. They didn't give you a path. Any idea why not?
 
Smazmbazm said:
Here is the whole question

http://imgur.com/KGI28pJ

[PLAIN]http://imgur.com/KGI28pJ[/QUOTE]
Just follow the questions in sequence. Use Gradient theorem. Like Gauss's and Stoke's theorems,
they are fancy version of FTC in Calc.
 
Last edited by a moderator:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..? What I find confusing is distinguishing between what dl, ds, and dr all mean in various contexts. Such as

∫_{C}F.ds

∫^{B}_{A}F.dl

and

∫_{C}F.dr

what are the differences between all these...?
 
Smazmbazm said:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..?

You get ##\vec{dl}## from the parametrisation of your path. So what path are you going to take? Why do you think the question has not specified a path?
 
Smazmbazm said:
Yea ok, I figured that out. So the path I got, following http://tutorial.math.lamar.edu/Classes/CalcIII/LineIntegralsPtI.aspx was r(t) = <t, t+1,3-t> and after evaluating the whole expression I got an answer of 5. Dunno if that's right because we aren't given answers to our questions for some silly reason -.-
Yes, that's right, but what justifies using the straight line parametrisation?
 
Is that because it's a conservative field and calculations are therefore path independent?
 
  • #10
Smazmbazm said:
Is that because it's a conservative field and calculations are therefore path independent?

Exactly.
 

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