Line integral over a Vector Field

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Homework Help Overview

The discussion revolves around calculating a line integral over a vector field defined by F(x,y,z) = (yz + 3x^{2})i + xzj + xy k, with specified points A = (0,1,3) and B = (1,2,2). Participants are exploring the concept of the differential element dl and its relation to the path taken in the integral.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the definition of dl and how it relates to the path of integration. There is uncertainty about setting the limits of integration and distinguishing between different differential elements such as dl, ds, and dr. Some participants discuss potential paths for integration and the implications of using a straight line parametrization.

Discussion Status

Some participants have identified a path for integration and have attempted to evaluate the integral, while others are still clarifying the concepts of dl and the conditions under which the integral can be evaluated. There is a recognition that the field may be conservative, which could imply path independence.

Contextual Notes

Participants note the absence of a specified path in the problem statement, leading to discussions about how to determine dl based on different paths. There is also mention of homework constraints regarding the lack of provided answers for verification.

Smazmbazm
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Homework Statement



Given a vector field

F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}

Calculate the line integral

∫_{A}^{B}F\bullet dl

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz ?

Thanks for any assistance.
 
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Smazmbazm said:

Homework Statement



Given a vector field

F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}

Calculate the line integral

∫_{A}^{B}F\bullet dl

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz ?

Thanks for any assistance.

No, dl isn't equal to (dx,dy,dz) in general. dl depends on the path you are integrating along. They didn't give you a path. Any idea why not?
 
Smazmbazm said:
Here is the whole question

http://imgur.com/KGI28pJ

[PLAIN]http://imgur.com/KGI28pJ[/QUOTE]
Just follow the questions in sequence. Use Gradient theorem. Like Gauss's and Stoke's theorems,
they are fancy version of FTC in Calc.
 
Last edited by a moderator:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..? What I find confusing is distinguishing between what dl, ds, and dr all mean in various contexts. Such as

∫_{C}F.ds

∫^{B}_{A}F.dl

and

∫_{C}F.dr

what are the differences between all these...?
 
Smazmbazm said:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..?

You get ##\vec{dl}## from the parametrisation of your path. So what path are you going to take? Why do you think the question has not specified a path?
 
Smazmbazm said:
Yea ok, I figured that out. So the path I got, following http://tutorial.math.lamar.edu/Classes/CalcIII/LineIntegralsPtI.aspx was r(t) = <t, t+1,3-t> and after evaluating the whole expression I got an answer of 5. Dunno if that's right because we aren't given answers to our questions for some silly reason -.-
Yes, that's right, but what justifies using the straight line parametrisation?
 
Is that because it's a conservative field and calculations are therefore path independent?
 
  • #10
Smazmbazm said:
Is that because it's a conservative field and calculations are therefore path independent?

Exactly.
 

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