Line Integral Solution for Curve γ: Simplifying Substitutions

  • Thread starter Thread starter Graham87
  • Start date Start date
  • Tags Tags
    Line integral
Click For Summary

Homework Help Overview

The discussion revolves around solving a line integral along a specified curve γ within the context of vector fields. Participants are exploring the complexities of substitutions and the potential path independence of the integral.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to apply relations for line integrals but find the substitutions challenging. Questions about the relationship between components of the vector field and the possibility of the field being conservative are raised. Some suggest comparing terms in expressions to glean insights.

Discussion Status

The discussion is ongoing, with participants providing guidance on examining the vector field's properties and suggesting checks for path independence. Multiple interpretations of the problem are being explored, particularly regarding the conservative nature of the field.

Contextual Notes

Participants mention the importance of start and end coordinates for the path and express uncertainty about the complexity of the problem. There are references to specific terms and derivatives within the vector field that may influence the approach taken.

Graham87
Messages
72
Reaction score
16
Homework Statement
Solve this line integral
Relevant Equations
see pictures
Hello,

How should I go about to solve this line integral along the line curve γ?
Screenshot 2023-12-03 183123.png

Screenshot 2023-12-03 183130.png
I attempt to apply this relation but the substitutions get too messy.
Screenshot 2023-12-03 183331.png


Thanks
 
Physics news on Phys.org
can you make any particular observations regarding the relation between the two components of your vector field?
 
  • Like
Likes   Reactions: Graham87
Orodruin said:
can you make any particular observations regarding the relation between the two components of your vector field?
I'm not sure. It looks overwhelmingly complicated to me.
Should I try to check if it is path independent?
 
Graham87 said:
I'm not sure. It looks overwhelmingly complicated to me.
Should I try to check if it is path independent?
You might want to consider the start and end coordinates of the path (corresponding to ##t=0## and ##t= \pi##). You might want to consider whether or not the field is conservative.

Edited.
 
  • Like
Likes   Reactions: Graham87
Graham87 said:
I'm not sure. It looks overwhelmingly complicated to me.
Should I try to check if it is path independent?
Compare the first terms of each expression. What do you see?
Do the same for the second and third terms. Same question.
Do the same for the fourth term (which is 0 for the x-component). Same question.

If you prefer to check in a different way if the field is conservative, please feel free to do so.
 
  • Like
Likes   Reactions: Graham87
Orodruin said:
Compare the first terms of each expression. What do you see?
Do the same for the second and third terms. Same question.
Do the same for the fourth term (which is 0 for the x-component). Same question.

If you prefer to check in a different way if the field is conservative, please feel free to do so.
Looks like some derivative or primitive function variation. But it's not in a series.
I might consider checking if the field is conservative. But I'm curious how it would be done by the other way?
 
Graham87 said:
Looks like some derivative or primitive function variation. But it's not in a series.
I might consider checking if the field is conservative. But I'm curious how it would be done by the other way?
There is really no "magic" too it. Just that ##3 x^2 y## is quite clearly the ##x##-derivative of ##x^3 y## ... of which ##x^3## is the ##y##-derivative, etc etc
 
  • Like
Likes   Reactions: Graham87

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K