Finding Polynomial Graphs Through Given Points with Linear Algebra

Click For Summary
SUMMARY

This discussion focuses on finding all polynomials of degree ≤ 2 that pass through the points (1,1) and (2,0) while satisfying the integral condition ∫ from 1 to 2 of f(t) dt = -1. Participants confirm that the polynomial can be expressed as y = ax² + bx + c, leading to a system of equations derived from the points and the integral. The equations a + b + c = 1, 4a + 2b + c = 0, and 7/3a + 3/2b + c = -1 are established, with emphasis on the importance of correctly applying the integral to find the coefficients a, b, and c.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Knowledge of definite integrals and their applications
  • Familiarity with systems of linear equations
  • Basic concepts of matrix operations, including dot products
NEXT STEPS
  • Study the process of solving systems of linear equations using matrices
  • Learn how to compute definite integrals of polynomial functions
  • Explore the relationship between polynomial degree and the number of conditions
  • Investigate the differences between dot products and matrix multiplication
USEFUL FOR

Students and educators in mathematics, particularly those focusing on algebra, calculus, and linear algebra concepts. This discussion is beneficial for anyone looking to deepen their understanding of polynomial interpolation and integral calculus.

frasifrasi
Messages
276
Reaction score
0
Ok, so I grasped how to some versions of this question, but one question in the book is
asking to find all the polynomials of degree <= 2 whose graphs run through the points (1,1) and (2,0) such that integral (from 1 to 2) of f(t) dt = -1.


I have never done anything like this, so if anyone can help, thank you
 
Physics news on Phys.org
Don't let the integral fool you! It's more of the same. What is the definite integral of ax^2+bx+c from 1 to 2? Do the definite integral and you will see that you still have the same three unknowns.
 
ok, but at what point do I apply the integral?
 
You have three conditions. Applying those conditions will still give you three linear equation in three unknowns. Compute the integral in terms of a,b and c.
 
Knowing that you can write the polynomial y= ax2+ bx+ c, what equation does x=1, y=1? x= 2, y= 0? x= 2, y= 0? And, of course, what equation, for a, b, and c, do you get from \int_1^2 (ax^2+ bx+ c)dx= -1?
 
I am doing the matrix for

a + b +c =1
and
4a + 2b + c =1

but het infinitely many solutions. Can you help me by saying if this is the correct matrix?
 
frasifrasi said:
I am doing the matrix for

a + b +c =1
and
4a + 2b + c =1

but het infinitely many solutions. Can you help me by saying if this is the correct matrix?

You have a third equation. Work out the integral Halls was kind enough to write out.
 
I know this is a stupid question, but I am getting

7/3a + 3/2b + c = -1 for the integral. Can anyone confirm this? It is just the answer doesn't seem right.
 
frasifrasi said:
I know this is a stupid question, but I am getting

7/3a + 3/2b + c = -1 for the integral. Can anyone confirm this? It is just the answer doesn't seem right.

That's right.
 
  • #10
Dick or anyone,

My book is terrible so I am having to research a lot of topics.

For the dot product of the col matrix
1
2
3

and

1
-2
1

I am getting
1
-4
3

just by multiplying, is this the correct way? how does this differ from matrix multiplication(cross product) once you are dealing with larger matrices?
 
  • #11
The dot product is the SUM of the products of the vector components. It's a scalar. In this case 1-4+3=0. If you work through matrix multiplication, you'll see you are building a matrix by taking dot products of row vectors and transposed column vectors.
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
18
Views
2K