Hey all. So I have been reading this article and have a question I would like to ask. I will be referring to this article extensively so it would be kind of you to open it: http://www.ee.ucr.edu/~yhua/MILCOM_2013_Reprint.pdf(adsbygoogle = window.adsbygoogle || []).push({});

I believe reading the article is not required to answer my questions (i did personally read it tho up until where I am stuck), but I will refer to the equation numbers in the article instead of typing them out here.

So, on page 5 of the pdf, there is a matrix,G, or equation number (22). I am basically trying to figure out how they constructed this matrix! Specifically the left two partitions._{2}

- Equation (15) gives the definition of
G, and shows thatGdepends onu(k).- Equation (12) defines
u(k) to be [u|_{1}^{T}u| ##\bar{g}##_{2}^{T}| 1].^{T}IT IS AT THIS POINT WHERE MY CONFUSION BEGINS

- The two lines after equation (12) define
uand_{1}^{T}u_{2}^{T}- Equation (5) defines ##\bar{g}##
,^{T}, andg_{i}^{T}g_{r}^{T}- Now that we have all the definitions stated we can go back to equation (22), or
G. It is stated in the two lines above equation (22) that m = 2 (m is the column size of ##\bar{g}##_{2}). Right?^{T}

That is my logic on this. I know I am doing something wrong, but I am not sure what it is. Please help me out here as I have been trying to understand this for a quite a bit. Thank you for read and your time : )

- Now if ##\bar{g}##
contains only two elements that means, according to equation (5),^{T}g, and_{i}^{T}gwould be scalars, right?_{r}^{T}- Continuing with this logic and going to the definition of
u, the difference of the Kronecker product of two scalars, would be zero! would it not? Hence,_{2}^{T}u= 0_{2}^{T}- According to the previous bullet point, this would make the second column/partition (from the left) of equation (22) equal to 0, which contradicts what is shown in equation (22)
- Doing the same with
uand the first column/partition (from the left) of equation (22) would also yield a different answer._{1}^{T}

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# Linear algebra and choosing training vector

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