Linear Algebra Help: Is L:R^2 -> R^2 a Linear Transformation?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 1K views
esler21
Messages
1
Reaction score
0
Is L:R^2 - ->R^2 defined by L(x,y) = (x-1,y-x) a linear transformation? Explain why or why not.



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Apply the properties of a linear transformation:
http://en.wikipedia.org/wiki/Linear_map#Definition_and_first_consequences

There are two properties to verify, as outlined in the link. For the first one, take two arbitrary elements of R2, you can call them (x1, y1) and (x2, y2), and see if they satisfy the first property. You may use the usual point wise addition for the ordered pairs.
Then take an arbitrary scalar to see if the second property is satisfied.

You might also find this page useful:
http://ltcconline.net/greenl/courses/203/Vectors/linearTransRn.htm