Linear Algebra Row Reduction: Solving a System of Equations with Row Operations

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SUMMARY

The discussion focuses on solving a system of equations using row reduction techniques in linear algebra. The specific equations presented are: x - 5y + 4z = -3, 2x - 7y + 3z = -2, and -2x + y + 7z = -1. The user attempts to achieve echelon form but struggles with eliminating the -9 in the third row without affecting the 15. The conversation highlights the importance of careful row operations and the potential for multiple solutions in systems of equations.

PREREQUISITES
  • Understanding of linear equations and systems
  • Familiarity with row operations in linear algebra
  • Knowledge of echelon form and reduced echelon form
  • Ability to perform Gaussian elimination
NEXT STEPS
  • Study Gaussian elimination techniques for solving systems of equations
  • Learn about echelon form and reduced row echelon form distinctions
  • Explore the concept of unique and infinite solutions in linear systems
  • Practice row operations with various systems of equations
USEFUL FOR

Students studying linear algebra, educators teaching mathematical concepts, and anyone looking to improve their problem-solving skills in systems of equations.

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Linear Algebra Row Reduction?

Homework Statement



This question is frustrating me, and I might be missing the obvious, I tend to make algebraic mistakes, but I don't know what I'm doing wrong here!

I'm trying to solve this system using row reduction:

x-5y+4z=-3
2x-7y+3z=-2
-2x+y+7z=-1

Note this does not have to be in reduced echelon form, just regular echelon form.





The Attempt at a Solution




Okay so I started like this:
Note: "l" indicated the bar representing "=" sign
1 -5 4 l -3
2 -7 3 l -2 --> I then used -2(2nd row)+1st row
-2 1 7 l -1 --> And 2(1st row)+ 3rd row

To get:

1 -5 4 l -3
0 3 -5 l 4
0 -9 15 l -7
I'm trying to remove the -9 in the third row but can't seem to do it without the 15 becoming zero.

Any help please?
 
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HINT: Some problems have more then 1 solution, some don't have any. [what is yours case?]
 

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