Linear Algebra, solution to homogeneous equation

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Homework Help Overview

The problem involves diagonalizing a square matrix and solving the homogeneous equation Bx=0, where B is a specific 3x3 matrix. The original poster is attempting to find the solution for the column vector x.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use row reduction to solve for the vector x but expresses confusion about the algebraic steps needed to arrive at the solution. They mention setting x3 as an arbitrary constant and question the reasoning behind their approach to x1.

Discussion Status

The discussion has progressed with the original poster identifying a method to reach the solution. However, they still seek clarity on the underlying reasoning for their approach, indicating an ongoing exploration of the concepts involved.

Contextual Notes

The original poster references a specific expected solution and expresses concern about understanding the algebraic manipulation involved in reaching that solution. There is also mention of the reduced row echelon form of the matrix B.

srfriggen
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Homework Statement



The problem has to do with diagonalizing a square matrix, but the part I'm stuck on is this:

Bx=0, where B is the matrix with rows [000], [0,-4, 0], and [-3, 0, -4].

After performing rref on the augmented matrix Bl0, I get rows [1,0,4/3,0], [0,1,0,0], [0000].

I am trying now to solve for column vector x=[x1,x2,x3]^transposed.



Homework Equations





The Attempt at a Solution





I'm stuck. From every other problem like this I would set x3 = r, where r is an arbitrary constant. x2 has a leading entry and I set that equal to zero, which seems to be the only thing I'm getting correct. I know the answer should be [-4,0,3]^transposed, so x1=-4, x2=0, x3=3 but I can't seem to algebraically get there.

Can someone let me know what I'm missing? Thank you!
 
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srfriggen said:

Homework Statement



The problem has to do with diagonalizing a square matrix, but the part I'm stuck on is this:

Bx=0, where B is the matrix with rows [000], [0,-4, 0], and [-3, 0, -4].

After performing rref on the augmented matrix Bl0, I get rows [1,0,4/3,0], [0,1,0,0], [0000].

I am trying now to solve for column vector x=[x1,x2,x3]^transposed.



Homework Equations





The Attempt at a Solution





I'm stuck. From every other problem like this I would set x3 = r, where r is an arbitrary constant. x2 has a leading entry and I set that equal to zero, which seems to be the only thing I'm getting correct. I know the answer should be [-4,0,3]^transposed, so x1=-4, x2=0, x3=3 but I can't seem to algebraically get there.

Can someone let me know what I'm missing? Thank you!





Ok, I now see that what works to get the answer is using the equation, x1+(3/4)r = 0, where r is an arbitrary constant. Setting r = 4, I have x1=-3, x2 = 0, and x3 = 4.

So I've figured out how to get to the solution, but I just don't understand why I should have used the equation x1 + (3/4)r = 0.

I'm going to keep plugging away at the intuition but if someone can help explain it to me I would be grateful. I don't like knowing how to do something without understanding what I'm doing.
 
Disregard, I've got it.

I realize that the rref form of B is equal to B*, and B*x yields the correct solutions.
 
Mark44 said:
Glad we could help out! :biggrin:



hahahaha! :smile:
 

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