Linear attenuation coefficient

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Homework Help Overview

The discussion revolves around determining the thickness of a foil made from a different absorber material that would provide the same x-ray attenuation as a specified thickness of another absorber. The context involves understanding the linear attenuation coefficient and its application in x-ray physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the thickness of the absorbers and their respective linear attenuation coefficients. There are attempts to apply the exponential attenuation formula and to manipulate it using logarithmic properties.

Discussion Status

Some participants have provided calculations and interpretations based on the attenuation formula, while others are exploring the implications of the linear attenuation coefficients for different materials. There is an ongoing examination of how changes in thickness relate to the coefficients.

Contextual Notes

Participants are working under the assumption that the x-ray energy is fixed, and they are comparing two different absorbers with specified linear attenuation coefficients. The problem involves understanding how these coefficients affect the required thickness for equivalent absorption.

jagguy
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Homework Statement


This i self study!
Hi, How thick should a foil made from absorber II be to give the same absoption as 1mm thick foil made from absorber I for xrays with energy 5X106


xray beam passing through an absorption material it is attenuated , this is given by

I/Io e-ax

io =initial intensity of the beam
i=intensity of beam from absorber taken as average amount of photons emerging from 1cm2
x=thickness of slab of absorbing material in cm-1
a=linear attenuation material
e=2.718

table photon energies 5X106
absorber 1 .4
absorber 2 .2

Homework Equations



linear attenuation coefficient=% reduced/thickness of absorber

The Attempt at a Solution



used logs to find x

tried to use linear attenuation coefficient
but really got stuck on what to do
 
Physics news on Phys.org
I/Io= e-ax
 
I/Io =e-ax
 
i go t an answer of 2mm because ax value where a is halved so x is doubled to keep same formula
 

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