Linear Dependence of Vectors: a, b, c

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SUMMARY

The vectors a = [1, -1, 0, 1], b = [1, 0, 0, 1], and c = [0, -1, 0, 1] are linearly independent. To determine this, one can represent the vectors in matrix form, either as rows or columns. The critical condition for linear independence is that the only solution to the equation a*x + b*y + c*z = 0 is x = y = z = 0. By solving the resulting equations, it is confirmed that the vectors do not yield a row or column of all zeros, thus establishing their independence.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically linear independence
  • Familiarity with matrix representation of vectors
  • Ability to solve systems of linear equations
  • Knowledge of vector notation and operations
NEXT STEPS
  • Study the definition and properties of linear independence in vector spaces
  • Learn how to perform Gaussian elimination on matrices
  • Explore the concept of span and its relation to linear independence
  • Practice solving systems of equations using matrix methods
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Students studying linear algebra, educators teaching vector spaces, and anyone interested in understanding the fundamentals of vector independence and matrix operations.

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Homework Statement


Are the vectors a = [1 -1 0 1], b = [1 0 0 1] and c =
[0 -1 0 1] linearly independent?


The Attempt at a Solution


I am mainly confused about whether or not I should have my matrix in row or column form to solve this:

r 1 -1 0 1
s 1 0 0 1
t 0 -1 0 1

or
r s t
1 1 0
-1 0 -1
0 0 0
1 1 1
 
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The standard method is to write the matrix having the vectors as columns. However, that is only a convention. Doing it the other way should give the same result- the vectors will be independent, doing this the first way, if you do NOT get a row of all 0s. Doing it writing the vectors as rows, the vectors will be independent if you do NOT get a column of all 0s.

However, if you have trouble remembering this, it appears you are trying to memorize a method that is, to you, arbitrary. Personally, I prefer to use the definition of "linear independent" which you should have learned anyway. A set of vectors is "linearly independent" if and only if the only linear combination that is equal to the 0 vector has all coefficients equal to 0. That is, in this case, if a<1, -1, 0, 1>+ b<1, 0, 0, 1>+ c<0, -1, 0, 1>= <0, 0, 0, 0> then we must have a= b= c= 0. Is that true?

Of course, that gives <a+ b, -a- c, 0, a+ b+ c>= <0, 0, 0, 0> or the three equations a+ b= 0, -a-c= 0, a+b+ c= 0. From the first b= -a and from the second, c= -a. Put those into the third equation and solve for a.
 

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