Linear Dependence and Non-Zero Coefficients

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Homework Help Overview

The discussion revolves around the concept of linear dependence and its implications regarding coefficients in a linear combination of vectors. The original poster presents a true or false statement regarding the conditions under which a linear combination equals zero.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of linear dependence and its relationship to the coefficients in the equation au+bv+cw=0. There is a focus on whether the statement about coefficients being non-zero holds true or false, with references to definitions and counterexamples.

Discussion Status

The discussion is ongoing, with participants questioning the original statement and the reasoning provided by the textbook. Some participants express confusion about the implications of linear dependence and the conditions under which coefficients can be zero.

Contextual Notes

There is a noted emphasis on the definitions of linear dependence and independence, as well as the implications of these definitions on the coefficients in the linear combination. The discussion also highlights a potential misunderstanding of the definitions involved.

Euler2718
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Homework Statement



True or False:

If u, v, and w are linearly dependent, then au+bv+cw=0 implies at least one of the coefficients a, b, c is not zero

Homework Equations



Definition of Linear Dependence:

Vectors are linearly dependent if they are not linearly independent; that is there is an equation of the form c_{1}v_{1}+c_{2}v_{2}+\dots+c_{n}v_{n} with at least one coefficient not zero

The Attempt at a Solution



I said true, but the book says false. It gives the reason, "for any vectors u, v, w - linearly dependent or not - 0u+0v+0w = 0" . But isn't the problem a direct restatement of the definition? Or am I missing something subtle here.
 
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Morgan Chafe said:

Homework Statement



True or False:

If u, v, and w are linearly dependent, then au+bv+cw=0 implies at least one of the coefficients a, b, c is not zero

Homework Equations



Definition of Linear Dependence:

Vectors are linearly dependent if they are not linearly independent; that is there is an equation of the form c_{1}v_{1}+c_{2}v_{2}+\dots+c_{n}v_{n} with at least one coefficient not zero

The Attempt at a Solution



I said true, but the book says false. It gives the reason, "for any vectors u, v, w - linearly dependent or not - 0u+0v+0w = 0" . But isn't the problem a direct restatement of the definition? Or am I missing something subtle here.
You're missing something subtle.
 
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If u, v, w linearly independent, au+bv+cw=0 implies a=b=c=0.
Inverting that, if u, v, w linearly dependent, au+bv+cw=0 does not imply a=b=c=0. But they still could be 0.
 
Thanks
 

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