Linear expansion distance problem

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Homework Help Overview

The discussion revolves around a problem involving linear expansion, specifically the measurement of distance between two lamp posts using a metal tape at varying temperatures. The original poster presents a scenario where the tape's reading is affected by temperature changes, leading to questions about the actual distance between the posts.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the derivation of formulas related to linear expansion and question the assumptions made regarding the original length of the tape versus the actual distance between the lamp posts. There are inquiries about the correctness of the calculations and the implications of temperature changes on the measurements.

Discussion Status

Some participants have provided calculations and derived formulas, while others have confirmed the reasoning behind the original poster's approach. There is an ongoing exploration of the implications of temperature on the measurements, but no explicit consensus has been reached regarding the final answer.

Contextual Notes

The problem is framed within the constraints of a hypothetical scenario, including specific temperature values and a defined coefficient of linear expansion. Participants are navigating the assumptions related to the tape's accuracy at different temperatures.

jsalapide
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On a hot day where the temperature is 32 degrees celsius, the distance between two lamp posts on the road is 30m as measured by a metal tape whose coefficient of linear expansion is hypothetically 50 x 10^-6 /degree Celsius. If the tape gives its correct reading at 20 degrees celsius, what is the actual distance between the lamp posts?
 
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How would you think to go about solving the problem?

Any equations come to mind?
 
i derived the formula alpha = change in L / (original length x change in temperature)
i came up with a formula original length = final length / (alpha x change in temperature + 1)
alpha is the coefficient of linear expansion..
I set the original length as the original length of the tape and not the actual distance between the 2 posts..
I got 29.98m
i subtracted it to 30m and i got 0.018m..
i added it to 30m to get the actual distance of the 2 posts..

My answer is 30.018m..

Is that right?
 
jsalapide said:
i derived the formula alpha = change in L / (original length x change in temperature)
i came up with a formula original length = final length / (alpha x change in temperature + 1)
alpha is the coefficient of linear expansion..
I set the original length as the original length of the tape and not the actual distance between the 2 posts..
I got 29.98m
i subtracted it to 30m and i got 0.018m..
i added it to 30m to get the actual distance of the 2 posts..

My answer is 30.018m..

Is that right?

Looks right. If the tape was cooled by 12 degrees it would contract by .018 m. Hence it will read higher than the measure at the warmer temperature by that amount.
 

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