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- Thread starter jsalapide
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- #1

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- #2

LowlyPion

Homework Helper

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How would you think to go about solving the problem?

Any equations come to mind?

Any equations come to mind?

- #3

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i came up with a formula original length = final length / (alpha x change in temperature + 1)

alpha is the coefficient of linear expansion..

I set the original length as the original length of the tape and not the actual distance between the 2 posts..

I got 29.98m

i subtracted it to 30m and i got 0.018m..

i added it to 30m to get the actual distance of the 2 posts..

My answer is 30.018m..

Is that right?

- #4

LowlyPion

Homework Helper

- 3,090

- 5

i came up with a formula original length = final length / (alpha x change in temperature + 1)

alpha is the coefficient of linear expansion..

I set the original length as the original length of the tape and not the actual distance between the 2 posts..

I got 29.98m

i subtracted it to 30m and i got 0.018m..

i added it to 30m to get the actual distance of the 2 posts..

My answer is 30.018m..

Is that right?

Looks right. If the tape was cooled by 12 degrees it would contract by .018 m. Hence it will read higher than the measure at the warmer temperature by that amount.

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