Just a quickie:(adsbygoogle = window.adsbygoogle || []).push({});

A particle is in the first excited Eigenstate of energy E corresponding to the one dimensional potential V(x) = [tex]\frac{Kx^2}{2}[/tex]. Draw the wavefunction of this state, marking where the particles KE is negative.

Now my question.

The first excited state will be n=1 correct? The first excited state is not the ground state under a different name is it?

So if it is n=1, then the wavefunction will look like a sin wave? And the KE will be negative on the left hand side of the sin wave (i.e. where a graph of sin(x) will be negative.)?

Ta guys.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Linear Harmonic Oscilator - QM

**Physics Forums | Science Articles, Homework Help, Discussion**