Linear Momentum - One-Dimensional Internal Explosion

In summary, the rear part of the body moves at a slower speed (v1=4.0 m/s) than the forward part (v2=8.0 m/s). The total linear momentum of the system is conserved, and the internal explosion increases the kinetic energy by 16 J.
  • #1
phyzmatix
313
0
[SOLVED] Linear Momentum - One-Dimensional Internal Explosion

1. A body is traveling at 2.0m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion separates the body into two parts, each of 4.0 kg, and increases the total kinetic energy by 16 J. The forward part continues to move in the original direction of motion. What are the speeds of (a) the rear part and (b) the forward part?



2. I know that, since the system is isolated (no net external force acts on the system), the total linear momentum is conserved. What I'm not sure of, is if the system can also be treated as an inelastic (since kinetic energy isn't conserved) collision. Lastly, since the question asks for the speeds of the two pieces, we know that only magnitude need to be calculated and that direction isn't of consequence.



3. Note: I tried the Latex references, but it's a bit time-consuming, so I'll just write my train of thought down as clearly as possible. Please bear with me.

The initial mass of the body is 8.0 kg (two 4.0 kg pieces) and initial velocity is 2.0 m/s. This gives the initial linear momentum as 16 kg m/s. Since the body separates into two equal parts of 4.0 kg each, we can set this momentum equal to 4.0kg(v1 + v2) which finally gives the value of the combined velocities of the two pieces as v1 + v2 = 4.0 m/s.

This is where I get stuck. With no additional information other than that the forward part continues in the original direction of motion, I am unsure as to what portion of the 4.0 m/s I should allocate to which piece.

At first, I thought I could use the given increase in the total kinetic energy of the system (16 J) in another equation involving the relevant velocities and then to solve the two equations simultaneously, but can't seem to get that right either. This is what I got

Tot KE before explosion + increase in KE = KE of piece 1 + KE of piece 2 (after explosion)
which gives
16 J + 16 J = 2(v1^2 + v2^2)
v1^2 + v2^2 = 16 J

and as you can see, this doesn't really bring us any closer to anything useful since it basically boils down to the values we got for the conservation of linear momentum.

Any pointers or ideas will be greatly appreciated. So far I've only managed to discover examples of explosions in two dimensions or ones where a lot more information is provided.

I have this feeling that I'm standing and staring at the obvious, but that it's very well camouflaged against the background of my inexperience :)
 
Physics news on Phys.org
  • #2
You are doing fine.

You have two equations (one from momentum and one from energy) and two variables (v1 and v2). Solve!

Hint for solving: Express one speed in terms of the other (using the momentum equation) and then substitute that expression into the other equation. Solve the quadratic.
 
  • #3
Thanks Doc! I guess re-learning the basics is the price I'll have to pay for only starting a degree when I'm well on my way to 30... :smile:
 

1. What is linear momentum?

Linear momentum is a measure of an object's motion in a straight line. It is calculated by multiplying an object's mass by its velocity.

2. What is a one-dimensional internal explosion?

A one-dimensional internal explosion is a type of explosion that occurs within a confined space, where the energy released is transferred in only one direction. This type of explosion is often seen in gas or chemical reactions.

3. How is linear momentum conserved in a one-dimensional internal explosion?

In a one-dimensional internal explosion, the total linear momentum before and after the explosion remains constant. This is because there are no external forces acting on the system, so the total momentum must be conserved.

4. What factors affect the linear momentum of an object in a one-dimensional internal explosion?

The linear momentum of an object in a one-dimensional internal explosion can be affected by factors such as the mass of the object, its initial velocity, and the magnitude of the explosion.

5. How can the conservation of linear momentum be used to analyze a one-dimensional internal explosion?

The conservation of linear momentum can be used to analyze a one-dimensional internal explosion by calculating the total momentum of the system before and after the explosion and ensuring they are equal. This can help determine the velocities of objects involved in the explosion and the direction of their motion.

Similar threads

  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
10
Replies
335
Views
8K
  • Introductory Physics Homework Help
Replies
31
Views
3K
  • Introductory Physics Homework Help
2
Replies
40
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
780
  • Introductory Physics Homework Help
Replies
16
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
2
Replies
38
Views
3K
Back
Top