a quarter back throws a pass that is a perfect spiral, and the spins at 7.7 rev/s. the linear speed is 19 m/s and at an angle 55. if the ball is caught the same height it is thrown, how many rev. has the ball made while in the air?
ω^2 = ωnot^2 + 2(alpha) (theta)
The Attempt at a Solution
ω^2= (48rad/s)^2+ 2(19m/s)(55) = 66.56 rad/2pi= 104.56 rev
this answer is not right...i think that alpha is something else like a/r but i dont have r...thanks for help