Linear Systems (differential equations)

Click For Summary

Homework Help Overview

The discussion revolves around the behavior of solutions to linear systems represented by differential equations, specifically focusing on the asymptotic behavior of the solution as time approaches infinity or negative infinity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of the eigenvalues (lambda1, lambda2) on the solution's behavior, questioning how the coefficients and the signs of the eigenvalues affect the overall solution as time varies.

Discussion Status

Some participants have provided clarifications regarding the growth or decay of the solution components based on the eigenvalues, while others are seeking confirmation of their reasoning about the overall behavior of the solution as a whole.

Contextual Notes

There is a focus on understanding the contributions of each term in the solution and how the coefficients influence the direction of the solution as time approaches infinity or negative infinity. Participants are also clarifying the definitions and roles of the constants involved.

EV33
Messages
192
Reaction score
0

Homework Statement



I don't have a homework question. I have more of a general question.

Let's say we have a solution...

x=C1*[a1 a2][tex]^{T}[/tex]*e[tex]^{lamda1*t}[/tex] + C2*[b1 b2][tex]^{T}[/tex]*e[tex]^{lamda2*t}[/tex]

As t approaches infinity how do you determine what the solution does?

Homework Equations





The Attempt at a Solution



My guess is that a1,a2,b1,b2 don't matter.

If lamda1>0,lamda2>0 , and lamda1>lamda2 then as t approaches infinity then x will look more like the first term. As t approaches negative infinity the solution will look more like the second term.

If lamda1>0 and lamda2<0 then as t approaches infinity the solution will look more like first term. When t approaches negative infinity the solution will look more like the second term.

The coefficients (C1,C2) help determine whether the solution will approach negative infinity or infinity as t approaches one or the other.

So if the dominant term has a positive lamda and a negative coefficient then the solution will approach negative infinity as t approaches infinity?

So do I have it right?

Thank you for your time.
 
Physics news on Phys.org
Just to clarify a few things.

T=transpose
t=variable
lamda1,lamda2,c1,c2,a1,a2,b1,b2= constants
 
It depends on whether lambda1 and lambda2 (the correct English spelling) are positive or negative.

Your solution x is the sum of two vectors. Let's look at each of them separately. If [itex]\lambda_1[/itex] > 0, then [itex]e^{\lambda_1 t}[/itex] approaches infinity as t approaches infinity. This means that the first vector in the sum is growing longer as t gets large.

If [itex]\lambda_1[/itex] < 0, then [itex]e^{\lambda_1 t}[/itex] approaches zero as t approaches infinity. This means that the first vector in the sum is getting shorter as t gets large.

The same kind of analysis can be done for [itex]\lambda_2[/itex], and its effect on the second vector.
 
Thank you that answers part of my question. I am trying to look at x as a whole though to see how x changes as t goes to infinity or negative infinity. I am curious if my thoughts for how the system as a whole is correct. In my first post I give a few specific examples. Were my assumptions correct?
 
What you said is mostly correct. The part that is incorrect is what you said about the solutions approaching infinity or negative infinity. The solution is a sum of two vectors, not a number.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K