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Linear Transformation: B-matrix [T]B

  1. Dec 6, 2011 #1
    1. The problem statement, all variables and given/known data
    Let V be polynomials, with real coefficients, of degree at most 2. Suppose that [itex]T:V→V[/itex] is differentiation. Find the [itex]B[/itex]-matrix [T]B if B is the basis of V
    B = {1+x, x+x2, x}


    2. Relevant equations
    For [itex]T:V→V[/itex] the domain and range are the same

    [T]B is the matrix whose i-th column is [itex][T(vi)]_B[/itex]

    [itex][T(v)]_C = A[v]_B[/itex] where [itex]A=[T]_B[/itex]


    3. The attempt at a solution
    So because the degree can be at most 2, the polynomials will be of the form a+bx+cx2. This can be denoted using a(1+x)+c(x+x2)+(b-a-c)(x). It will turn into a+bx (because we take the derivative, we take powers to a max of 1) and we would say a(1+x)+0(x+x2+b(x). After this, I'm not sure how to find the B-matrix, as I'm a bit confused as to what it is exactly.
     
  2. jcsd
  3. Dec 6, 2011 #2
    Well, you wrote down the formula. Here [itex] v_i [/itex] is a basis vector. So take T of each of your basis vectors, and then express [itex] T(v_i) [/itex] as a linear combination of the basis vectors.
     
  4. Dec 7, 2011 #3

    HallsofIvy

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    What is T(1+ x)? What is T(x+ x^2)? What is T(x)?
    Write each of those as a linear combination of 1+ x, x+ x^2, and x and the coefficients are the columns of your matrix.
     
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