Linear transformation from [-1,1] to [a,b]

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SUMMARY

The discussion centers on the linear transformation from the interval [-1, 1] to [a, b], specifically represented by the equation x = (2/(b-a)) * z - ((b+a)/(b-a)). A participant clarifies that this transformation is actually from [a, b] to [-1, 1]. The proof involves setting x = mz + c and applying boundary conditions to derive the values of m and c through simultaneous equations.

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mercuryman
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Hey
This is from Numerical analysis course (Legendre polynom) - they gave us the polynomial transformation from [-1,1] to [a,b] as: x = 2/(b-a) * z - (b+a)/(b-a)
what is the proof of this tranformation? where did it come from?
thanks
 
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mercuryman said:
Hey
This is from Numerical analysis course (Legendre polynom) - they gave us the polynomial transformation from [-1,1] to [a,b] as: x = 2/(b-a) * z - (b+a)/(b-a)
what is the proof of this tranformation? where did it come from?
thanks

That isn't the transformation from [-1,1] to [a,b]; it's the transformation from [a,b] to [-1,1].

As for where it comes from: set x = mz + c, and impose the conditions that x = -1 when z = a and x = 1 when z = b. That gives you two linear simultaneous equations for m and c:
<br /> -1 = ma + c \\<br /> 1 = mb + c<br />
 
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