Linear transformation one-to-one

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Homework Help Overview

The discussion revolves around the linear transformation defined by ##T:\mathbb{R^3} \rightarrow \mathbb{R^3}##, specifically examining whether T is one-to-one and if its range covers all of ##\mathbb{R^3}##.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to determine the one-to-one nature of the transformation by calculating the determinant of the associated matrix. Some participants question the correctness of this approach and the conclusions drawn from it.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the original poster's assertions regarding the transformation's properties. There is a suggestion that the original poster may already have a conclusion in mind.

Contextual Notes

Participants are considering the implications of the determinant being zero and how it relates to the transformation's injectivity and range. There may be assumptions about the understanding of linear transformations and their properties that are being explored.

jonroberts74
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Homework Statement


let ##T:\mathbb{R^3} \rightarrow \mathbb{R^3}## where ##T<x,y,z>=<x-2z,y+z,x+2y>##

Is T one-to-one and is the range of T ##\mathbb{R^3}##?

The Attempt at a Solution



I took the standard matrix A ##\left[\begin{array}{cc}1&0&-2\\0&1&1\\1&2&0\end{array}\right]##

det(A)=0 so by equivalence T is not one-to-one and by equivlence again the range is not ##\mathbb{R^3}##
 
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What is your question?
 
is that correct?
 
I suspect you already know the answer is yes.
 

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