Linear Velocity at Top (Rotational Kinematics)

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SUMMARY

The discussion centers on calculating the linear velocity at the top of a bike tire moving at X m/s, with tires measuring 0.60 m in diameter. The formula v = rω is utilized, where v represents linear velocity, r is the radius, and ω is angular velocity. It is concluded that the speed of the topmost point of the tire relative to the ground is 2X m/s, while the instantaneous velocity at the point of contact with the ground is 0 m/s. This highlights the relationship between linear and angular velocities in rotational kinematics.

PREREQUISITES
  • Understanding of rotational kinematics concepts
  • Familiarity with the formula v = rω
  • Knowledge of angular velocity and its relation to linear velocity
  • Basic grasp of static friction effects on rolling objects
NEXT STEPS
  • Study the relationship between linear and angular velocities in depth
  • Explore the implications of static friction on rolling motion
  • Learn about the dynamics of rotational motion in bicycles
  • Investigate the effects of tire diameter on velocity calculations
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Physics students, mechanical engineers, and anyone interested in understanding the principles of rotational kinematics and their applications in real-world scenarios like cycling.

ddrtrinity
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1. A bike is moving at X m/s. Its tires are .60 m in diameter. How fast is a point at the rim of the top of one of the wheels moving relative to the ground?



2. v = r omega, C = 2 pi r (?)



3. At first we thought he just wanted angular velocity. Then when we realized that his given velocity is for the axle, and that he wanted velocity compared to the ground. Then we thought perhaps it is the same, but this wouldn't be true since linear velocity would depend on the radius. When I looked at a figure in the textbook, it appeared that the linear velocity for the top at anyone instant would be 0 m/s, no matter what the angular velocity was, since it opposes the bottom with static friction. So ultimately, we are just very confused.
 
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v=rw, (w is omega) where v is the speed of the bike and also the axle. The topmost point has a horizontal speed v wrt the axle. So, the speed of the topmost point is 2v wrt the ground (or 2X m/s as given by you). This is only the instantaneous velo, mind you.

The instantaneous velo of the pt of contact is zero.
 

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