Linearization of non linear systems

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Linearization of non-linear systems involves approximating behavior around equilibrium points where the state derivatives are zero. Setting x' = 0 identifies these equilibrium points, which represent stable or unstable conditions of the system. This method does not solely yield maximum or minimum values of x but provides insights into the system's dynamics near those points. Understanding the behavior around equilibrium helps in analyzing stability and response to perturbations. Clarifying this concept is essential for effective dynamics modeling.
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Homework Statement


In my dynamics modelling class, the professor went over an example where we linearize non linear state equations to approximate the behavior. In this case, we are not given an operating point. However, the professor said you can solve for the operating point by setting x' = 0. See the picture below for the notes.

I don't really understand why we can do this, if we set x' = 0, doesn't this just solve for the max and min values of x. For example if x = displacement, then we get the max and min displacements at a certain point. I tried to do some research but I am still confused.

Homework Equations


x' = f(x,u)

The Attempt at a Solution


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A dynamic system can have equilibrium points, where the velocities (##\dot x_i##-s ) are zero, and investigate the motion of the system around these points: If moving out the system slightly from equilibrium, it returns back or goes away, and there are some other possibilities.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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