Lines resolved by the instrument

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utkarshakash
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Homework Statement


A spectroscopic instrument can resolve two nearby wavelengths λ and λ+Δλ if λ/Δλ is smaller than 8000. This is used to study the spectral lines of the Balmer series of hydrogen. Approximately how many lines will be resolved by the instrument.

The Attempt at a Solution



For Balmer series

[itex]\dfrac{1}{\lambda} = R_H \left( \dfrac{1}{2^2} - \dfrac{1}{n^2} \right)[/itex]

Homework Statement



But what should I substitute for n?
 
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utkarshakash said:

Homework Statement


A spectroscopic instrument can resolve two nearby wavelengths λ and λ+Δλ if λ/Δλ is smaller than 8000. This is used to study the spectral lines of the Balmer series of hydrogen. Approximately how many lines will be resolved by the instrument.

The Attempt at a Solution



For Balmer series

[itex]\dfrac{1}{\lambda} = R_H \left( \dfrac{1}{2^2} - \dfrac{1}{n^2} \right)[/itex]

Homework Statement



But what should I substitute for n?

n is 3, 4, 5, 6, 7, 8, ...any positive integer >2. You get a wavelength for each n. Find that N so that λ(N)/(λ(N-1)-λ(N))<8000, but λ(N)/(λ(N)-λ(N+1))>8000

ehild
 
Last edited:
ehild said:
n is 3, 4, 5, 6, 7, 8, ...any positive integer >2. You get a wavelength for each n. Find that N so that λ(N)/(λ(N-1)-λ(N))<8000, but λ(N)/(λ(N)-λ(N+1))>8000

ehild

I'm facing difficulty finding the n. I tried forming an equation but it is not easy to solve. Hit and trial method does not work for me.
 
Last edited:
You know that the change of a function can be estimated as Δf(x)=(df/dx) Δx.
Your function is λ(n). Take the derivative, and write Δλ/λ as function of n, with Δn=1.

What is the equation you arrive at? It is not easy to solve, you need to estimate. How big can be n? 5? 10? 50? 1000?

Estimation and trial is a method, frequently applied.


ehild