(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a piece of metal of 10cm X 20 cm X 5 cm is sitting flat on the bottom of water basket, with one of the 10cm X 20cm sides facing up. the metal has density of 19.3 g/cm3. The basket is filled with water(full). The backet has a radius of 0.25m and a hight of 1m, density of water 1g/cm3.

What is the total force acting on the metal?

a) 9800N

b) 196 N

c) 19.3 N

d) 1.00N

e) none of the above

2. Relevant equations

P = pgh, F= PA

3. The attempt at a solution

The question asks for total force. So i first assumed they are asking for total net force. Considering the bottom of the metal does not touch water, i think there is no bouyancy. So the only net force acting on it is the pressure from water above the metal.

The surface area = 0.2 m X 0.1m = 0.02 m2

depth of water = 0.95m

volume of water above the metal v = 0.95X0.02 = 0.019 m3

Gwater = 0.019 X 1000kg/m3 X 9.8 n/kg = 186.2 N

but there is no 186.2 N in the question, i did it using P = pgh and still gets the same thing, what could it be?

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# Liquid pressure multiple choice

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