A square pool with 100-m-long sides is created in a concrete parking lot. The walls are concrete 90 cm thick and have a density of 2.5 g/cm3. The coefficient of static friction between the walls and the parking lot is 0.49. What is the maximum possible depth of the pool? (The density of water is 1000 kg/m3.)
P = F/A, rho=m/v
The Attempt at a Solution
I've been at this one for the past two days. I cannot find a way to approach this as I think I have an idea.
The density of the wall is given, therefore I can determine how much pressure the wall can take with a variable h(max depth).
Wit that I can take that as my net force to determine the height with a given amount of water in the pool.
A couple attempts: I converted 2.5 g/cm^3 to 2500 kg/m^3
I used integration to find the total amount of force the wall can handle
Ftotal = ∫ ρgh (100 dh), limits of integration 0 to y
I'm just completely stumped here.