Liquid pressure multiple choice

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SUMMARY

The discussion centers on calculating the total force acting on a submerged metal piece with dimensions 10cm x 20cm x 5cm and a density of 19.3 g/cm³, placed in a water-filled basket. The relevant equations used are P = pgh for pressure and F = PA for force. The calculated force from the water above the metal is 186.2 N, which does not match any of the provided multiple-choice answers. The confusion arises from the assumption that buoyancy does not apply, despite the metal being submerged.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically buoyancy and pressure calculations.
  • Familiarity with the equations P = pgh and F = PA.
  • Knowledge of unit conversions between grams, centimeters, and meters.
  • Basic understanding of density and its implications in fluid contexts.
NEXT STEPS
  • Review the concept of buoyancy and its effect on submerged objects.
  • Practice calculating forces in fluid systems using different densities and dimensions.
  • Explore the implications of pressure at varying depths in fluids.
  • Learn about Archimedes' principle and its applications in real-world scenarios.
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Students studying physics, particularly those focusing on fluid mechanics, as well as educators looking for practical examples of pressure and buoyancy calculations.

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Homework Statement


a piece of metal of 10cm X 20 cm X 5 cm is sitting flat on the bottom of water basket, with one of the 10cm X 20cm sides facing up. the metal has density of 19.3 g/cm3. The basket is filled with water(full). The backet has a radius of 0.25m and a height of 1m, density of water 1g/cm3.

What is the total force acting on the metal?
a) 9800N
b) 196 N
c) 19.3 N
d) 1.00N
e) none of the above

Homework Equations


P = pgh, F= PA


The Attempt at a Solution



The question asks for total force. So i first assumed they are asking for total net force. Considering the bottom of the metal does not touch water, i think there is no bouyancy. So the only net force acting on it is the pressure from water above the metal.

The surface area = 0.2 m X 0.1m = 0.02 m2
depth of water = 0.95m
volume of water above the metal v = 0.95X0.02 = 0.019 m3
Gwater = 0.019 X 1000kg/m3 X 9.8 n/kg = 186.2 N

but there is no 186.2 N in the question, i did it using P = pgh and still gets the same thing, what could it be?
 
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