Lissajous figure and oscilloscopes problem

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SUMMARY

The discussion focuses on the behavior of Lissajous figures on oscilloscopes, specifically how these figures transition from straight lines to circles based on the phase relationship between input signals. It is established that when two signals are in-phase, they produce a straight line, while a 90-degree phase difference results in a circular pattern, assuming equal frequencies. The horizontal time/div control setting on oscilloscopes affects the number of wave cycles displayed, with a 10ms/div setting showing approximately 5 cycles for a 60Hz signal. Understanding the non-linear horizontal sweep rate is crucial for creating Lissajous patterns.

PREREQUISITES
  • Basic knowledge of oscilloscopes and their controls
  • Understanding of signal phase relationships
  • Familiarity with Lissajous figures and their formation
  • Knowledge of frequency and period calculations
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  • Explore the use of oscilloscopes for visualizing Lissajous figures
  • Learn about the effects of phase differences on signal patterns
  • Investigate the mathematical principles behind Lissajous figures
  • Experiment with different time/div settings on oscilloscopes to observe wave cycle variations
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Electronics students, hobbyists working with oscilloscopes, and anyone interested in signal analysis and visualization techniques.

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i'm learning about oscilloscopes, and i don't understand
why this Lissajous figure can be go from a straight line to
a circle. Also, this sweep time/div control setting, i dont
understand why the wave cycles vary with this control setting.
 
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You questions are not very clear and are therefore had to answer.
Here is a java applet for lissajous lab. It did not work with my browser but maybe it will for yours.
http://www.math.com/students/wonders/lissajous/lissajous.html
here is one that worked on my browser.
http://abc.net.au/science/holo/liss.htm

The oscilloscope takes some getting use to. Play with it a little and don’t be afraid of breaking it, most are rather resilient. I have only seen people mess up oscilloscopes when they mess with the output impendence of the oscilloscope.
 
The horizontal time setting (time/div) controls the time it take the sweep to cross the screen. It is specified as the time required to travel 1 major division on the screen. If you are displaying periodic signal the number of cycles on the screen will be determined by the horizontal time setting. So if you are looking at a 60hz it has a period of ~17ms. So a setting of 10ms/div will mean that 1 cycle of the signal will occur in about 1.7 divisions. If there are 10 divisions across the screen you will see about 5 cycles. Now if you change the time base to 5ms/division each cycle will take about 3 divisions and only ~3 cycles will be displayed.

To create Lissajous patterns you must provide a signal to drive the horizontal sweep. This means that your horizontal speed controls are disabled. The normal signal applied to the horizontal deflection is a sawtooth, this causes the sweep to cross the screen at the uniform rate specified by the time base. When you apply a sinusoidal signal to the horizontal plates the rate the sweep travels is no longer linear, it now varies with the phase of the input signal. When you apply equal frequencies to both horizontal and vertical plates the result is the circle. The appearance of the pattern is determined by the ration of the horizontal to vertical frequency. A figure 8 means a 2:1 ratio, a 1:2 yields a \infty Higher ratios yield more interesting results.

The key to understanding the Lissajous pattern is realize that the horizontal sweep rate is not linear.
 
Last edited:
figs said:
i'm learning about oscilloscopes, and i don't understand
why this Lissajous figure can be go from a straight line to
a circle.

If your two inputs are in-phase, they will produce a straight line, if they are 90 degrees out of phase, they will produce a circle (provided the two inputs are the same frequency of course).

Claude.
 
Claude Bile said:
If your two inputs are in-phase, they will produce a straight line, if they are 90 degrees out of phase, they will produce a circle (provided the two inputs are the same frequency of course).

Claude.
Yes, reflecting on my post, I realized that I had neglected to mention the importance of the phase relationship between the signals. Thank you Claude.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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