Lithium Hydroxide 0.602mole Calculation
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The discussion centers on the calculation of lithium hydroxide (LiOH) production from lithium nitride (Li3N) and water (H2O) through stoichiometric relationships. The balanced chemical equation is Li3N + 3 H2O → 3 LiOH + NH3. Participants clarify the concept of limiting reagents, determining that water is the limiting reagent when 2.5 moles of Li3N are mixed with 4.5 moles of H2O, resulting in the formation of 1.5 moles of ammonia (NH3). The importance of understanding stoichiometric coefficients and the limiting reagent concept is emphasized for accurate calculations.
PREREQUISITES- Understanding of stoichiometry and chemical reactions
- Familiarity with limiting reagents in chemical equations
- Basic knowledge of mole calculations and conversions
- Ability to interpret and balance chemical equations
- Study stoichiometric calculations using the ideal gas law
- Learn about limiting reagents and their impact on chemical yields
- Explore the concept of molarity and its applications in solution chemistry
- Review examples of stoichiometric problems involving different reactants
Chemistry students, educators, and anyone involved in chemical engineering or laboratory work who seeks to deepen their understanding of stoichiometric calculations and limiting reagents in chemical reactions.
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0.602 mole is not an answer to any of the questions asked. 14.4g is much better.
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But in part a, they asked to find number of moles.
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Sorry, my mistake, somehow I read they just asked about mass in the first part of the question, and moles in the second. That's partially because you entered question as an image - I had to switch between the answer and the question, it doesn't help.
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Ok, I'm sorry too for putting the question on image.
If the number of moles in part a is correct, please give me a hint how should approach part b, where they ask how many moles of ammonia can be formed if 2.5moles of lithium nitride is mixed with 4.5moles of water
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n= (18.01*7)/(54+34.83)
n=1.419 mole.
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No. Forget about masses, calculate just number of moles.
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n=7/4 mole ?
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Where did you got 7 and 4 from?
Take a look at the reaction equation.
http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations
How many moles of LiOH can be produced from 1 mole of lithium nitride? From 2.5 mole of nitride?
How many moles of LiOH can be produced from 1 mole of water? From 4.5 mole of water?
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How many moles of LiOH can be produced from 1 mole of lithium nitride? From 2.5 mole of nitride?
How many moles of LiOH can be produced from 1 mole of water? From 4.5 mole of water?[/QUOTE]
From 2.5mole of lithium nitride, we have 2.5*3mole of LiOH
From 4.5mole of water , we have 4.5 mole of LiOH
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chawki said:From 2.5mole of lithium nitride, we have 2.5*3mole of LiOH
From 4.5mole of water , we have 4.5 mole of LiOH
So, which one is a limiting reagent and what is the final answer?
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You mix 1 mole of hydrogen and 1000000 moles of chlorine - how many moles of HCl would you get?
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Borek said:H2 + Cl2 -> 2HCl
You mix 1 mole of hydrogen and 1000000 moles of chlorine - how many moles of HCl would you get?
Please tell me
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How many moles of HCl can be produced from 1 mole of hydrogen? How many moles of Cl2 are needed for that? Do we have that much chlorine?
How many moles of HCl can be produced from 1000000 moles of chlorine? How many moles of H2 are needed for that? Do we have that much hydrogen?
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Borek said:Take a look at the reaction equation and stoichiometric coefficients.
How many moles of HCl can be produced from 1 mole of hydrogen? How many moles of Cl2 are needed for that? Do we have that much chlorine?
How many moles of HCl can be produced from 1000000 moles of chlorine? How many moles of H2 are needed for that? Do we have that much hydrogen?
we can get 2 moles of HCl from 1 mole of hydrogen and 1 mole of Cl2
i used to have a method like '' x-number of moles'' but i forgot it :(
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The amount of product HCl will depend on the limiting reagent.
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wanna give me an example ?
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[PLAIN]http://www.chem.tamu.edu/class/majors/tutorialnotefiles/cars.gif
In this example, you only need 32 tires to put those 8 car bodies to good use. Since there is excess tires after the reaction (cars getting the tires installed), the bodies are what limit the reaction.Sometimes it is hard to tell which of the reactants will limit the product. If that is the case, you need to use one given reactant and express it in terms of moles of the other reactant. If that is greater than the second given reactant, then you "need" more of that second reactant, and so that is the limited reactant.The ratio of H to Cl in your balanced equation is 1/1...
http://www.khanacademy.org/video/stoichiometry--limiting-reagent?playlist=Chemistry
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Borek said:So, which one is a limiting reagent and what is the final answer?
limiting reagent is H2O because the ratio Li3N/H2O = 1/3 =2.5/(3*2.5) = 2.5/7.5
we have too much H2O than we need
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Li3N + 3 H2O ----> 3 LiOH + NH3
we multiply by 1.5 in order to get 4.5 moles of the limiting reagent.
1.5 Li3N + 4.5 H2O ----> 4.5 LiOH + 1.5 NH3
so we will get 1.5 mol of NH3
i hope I'm right
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chawki said:limiting reagent is H2O because the ratio Li3N/H2O = 1/3 =2.5/(3*2.5) = 2.5/7.5
we have too much H2O than we need
If water is a limiting reagent, we can't have too much of it.
chawki said:so we will get 1.5 mol of NH3
Surprisingly, this is a correct answer. As I am not able to follow your line of thinking I am not convinced it is not accidental.
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Borek said:If water is a limiting reagent, we can't have too much of it.
Surprisingly, this is a correct answer. As I am not able to follow your line of thinking I am not convinced it is not accidental.
ok well, isn't water the limiting reagent ?
I just watched that video and learned from it.
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