Lithium Iron Disulfide Battery Chemistry

  • Thread starter greg136
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  • #1
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Main Question or Discussion Point

I've been researching Lithium Iron Disulfide Batteries, but I've been unable to find the half-equations for the Cathode and Anode.

Cathode - Iron Disulfide
Anode - Lithium
Electrolyte - Organic Solvent Blend (Propylene Carbonite, Dioxolane, Dimethoxyethane)

The overall equation is,

4Li + FeS(2) --> Fe + 2Li(2)S

Any help would be greatly appreciated.

Thanks in advance.
 

Answers and Replies

  • #2
Borek
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No idea what is exactly happening in these batteries, but just looking at overall equation it is obvious what is getting oxidized and what is getting reduced, so half reactions seem pretty straghtforward.

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  • #3
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so half reactions seem pretty straghtforward.
Not for me, I've not done chemistry since GCSE :S

Anyway, this is what I've come up with,

Li --> Li(+) + e-

and

FeS(2) + 4Li(+) + 4e- -- > Fe + 2Li(2)S

How do they look?

Cheers
 
  • #4
Borek
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28,326
2,713
First one - lithium oxidation - is OK. There is a problem with the other one, as you have mixed both half reactions together. You need something like FeS2 -> Fe + S22-, just balanced with electrons so that charge is identical on both sides.

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  • #5
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Ok, thanks for that.
 

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