Lithium Iron Disulfide Battery Chemistry

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SUMMARY

The discussion centers on Lithium Iron Disulfide (Li-FeS2) battery chemistry, specifically the half-reactions for the cathode and anode. The cathode reaction involves Iron Disulfide (FeS2) while the anode reaction involves Lithium (Li). The overall reaction is represented as 4Li + FeS(2) --> Fe + 2Li(2)S. Participants clarify the half-reactions, with the correct oxidation of lithium as Li --> Li(+) + e- and the cathode reaction needing adjustment to FeS2 -> Fe + S2(2-) to ensure charge balance.

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  • Understanding of electrochemistry principles
  • Familiarity with oxidation and reduction reactions
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greg136
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I've been researching Lithium Iron Disulfide Batteries, but I've been unable to find the half-equations for the Cathode and Anode.

Cathode - Iron Disulfide
Anode - Lithium
Electrolyte - Organic Solvent Blend (Propylene Carbonite, Dioxolane, Dimethoxyethane)

The overall equation is,

4Li + FeS(2) --> Fe + 2Li(2)S

Any help would be greatly appreciated.

Thanks in advance.
 
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No idea what is exactly happening in these batteries, but just looking at overall equation it is obvious what is getting oxidized and what is getting reduced, so half reactions seem pretty straghtforward.

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methods
 
Borek said:
so half reactions seem pretty straghtforward.

Not for me, I've not done chemistry since GCSE :S

Anyway, this is what I've come up with,

Li --> Li(+) + e-

and

FeS(2) + 4Li(+) + 4e- -- > Fe + 2Li(2)S

How do they look?

Cheers
 
First one - lithium oxidation - is OK. There is a problem with the other one, as you have mixed both half reactions together. You need something like FeS2 -> Fe + S22-, just balanced with electrons so that charge is identical on both sides.

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Ok, thanks for that.
 

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