Why do electrical generators experience load effects?

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Electrical generators experience load effects because the load current creates a torque that counteracts the mechanical input torque, resulting in a decrease in generator efficiency. This phenomenon is a result of the motor action inherent in generators, as they function similarly to motors under load. When multiple generators are used to share the load, the division of torque can potentially reduce the overall drag on the system, although the total energy output remains constant due to the conservation of energy principle. Understanding these dynamics is crucial for optimizing generator performance under varying load conditions. Ultimately, effective management of load distribution can enhance generator efficiency.
Bloc911
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I was wondering why it is when you use the electricity from an electrical generator, it bogs the generator down? Shouldn't the draw off of electricity negate any sort of back flow there by making it easier on the generator to function?
 
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Conservation of energy is immutable. When the generator is loaded, the load current produces a torque which counters the input mechanical torque. This is motor action. Generators are motors as well, & vice-versa.

Claude
 
Ty cabraham, I will soon be working a generator system and was curious about the effects of loading on generators. I had guessed that such was the case but figured it would be better to ask. Hopefully soon I will be able to set my system. From the figures is have been working with I should be in the clear on the power to crank the generators under load as I will have 5 generators to split the load. Hopefully dividing the torque between them should be such that even though it will still be the same overall amount the division will produce less drag on the whole. I am guessing anyway. I will have to wait until I get it up and running to test it out.
 
Just note that no matter what, the system will obey Conservation of Energy.
 
Noted ty.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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