Local Max/Min and saddle points

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ahhppull
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Homework Statement



Find the local max/min or saddle points of f(x,y) = (x-y)(1-xy)

Homework Equations





The Attempt at a Solution



I expanded the equation to f(x,y) = x-y-(x^2)y+xy^2.

Then I found the partial derivatives of the function.
fx = 1-2xy +y^2
fy = -x^2-2xy

I'm stuck after this part. Usually I can set the function to 0 and solve for x or y, but I can't do that here.
 
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ahhppull said:

Homework Statement



Find the local max/min or saddle points of f(x,y) = (x-y)(1-xy)

Homework Equations





The Attempt at a Solution



I expanded the equation to f(x,y) = x-y-(x^2)y+xy^2.

Then I found the partial derivatives of the function.
fx = 1-2xy +y^2
fy = -x^2-2xy

I'm stuck after this part. Usually I can set the function to 0 and solve for x or y, but I can't do that here.

Your fy is incorrect.

RGV
 
Oh, I managed to type out the whole fy wrong.

It is -x^2 -1 +2yx
 
SammyS said:
So, can you solve the problem now?

No. I don't know how to solve for 0. I can't set both y or x on either side of the equation.
 
SammyS said:
Solve these equations simultaneously:

1-2xy +y2 = 0

-x2 -1 +2yx = 0

Use elimination: add them together.

Thanks man, figured it out
 
Ray Vickson said:
So what solution or solutions do you get?

RGV

Oh, I got saddle points at (1,1) and (-1,-1)