Solve Logarithms with Ease: 2log10 + log10(1/2 + 1/3) + 1/3log27 Explained

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The discussion focuses on evaluating the expression 2log10 + log10(1/2 + 1/3) + 1/3log27 without using logarithm tables. A participant initially struggles with the calculation, particularly with log10(1/2 + 1/3), mistakenly applying logarithmic properties. After clarification, they realize that 1/2 + 1/3 equals 5/6, leading to the correct evaluation of log10(5/6). Ultimately, the participant confirms that they arrived at the correct answer of 1 after correcting their approach. This highlights the importance of accurately applying logarithmic rules in calculations.
lionely
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Without using tables:

1. Evaluate 2log10 + log10(1/2 + 1/3) + 1/3log27

2log2 + log 1 - log2 + log1 - log3 + log3 = log2..

This was my attempt but it's wrong . I think I went wrong somewhere here log10(1/2 + 1/3) but I can't find the error.
 
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lionely said:
Without using tables:

1. Evaluate 2log102 + log10(1/2 + 1/3) + 1/3log27

2log2 + log 1 - log2 + log1 - log3 + log3 = log2..

This was my attempt but it's wrong . I think I went wrong somewhere here log10(1/2 + 1/3) but I can't find the error.
log(a + b) ≠ log(a) + log(b)


What is (1/2) + (1/3) ?
 
oh so it should be log(5/6) ?
 
Oh yes I got it! I got 1. Thanks for pointing that out.
 

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