- #1
dylanjames
- 24
- 0
Moved from a technical math section, so missing the template
I need to solve log3(2x+3)-log3(x-2)=3 where 3 is the base.
This is my attempt at a solution..
Log3(2x+3)-log3(x-2)=2
Log3(x-3/2)=2
Log3(x) - Log3(-3/2) = 2
Log3(x)-0.369=2
log3(x)=2.369
3^2.369=13.4
x=13.4
I plugged that into the original equation and I know it is not correct. Can anyone try to steer me in the right direction?
Been a while on this log business..
This is my attempt at a solution..
Log3(2x+3)-log3(x-2)=2
Log3(x-3/2)=2
Log3(x) - Log3(-3/2) = 2
Log3(x)-0.369=2
log3(x)=2.369
3^2.369=13.4
x=13.4
I plugged that into the original equation and I know it is not correct. Can anyone try to steer me in the right direction?
Been a while on this log business..