Logarithms questions need checking

  • #1
1. ln (x2 / y2)
= log (A / B) = logA-logB
= logx2-logy2
= 2logx - 2logy
(is this correct)

2. can this expression be split into seperate log functions and numbers, is this question the answer
log(2x + 3y) = log(2x + 3y)
(is this correct)
 

Answers and Replies

  • #2
867
0
What you have in 1. is correct, so you should be able to split, or expand, ln(x2/y2) correctly.
For 2., where did log(2x + 3y) = log(2x + 3y) come from?
 
  • #3
35,226
7,046
1. ln (x2 / y2)
= log (A / B) = logA-logB
= logx2-logy2
= 2logx - 2logy
(is this correct)

2. can this expression be split into seperate log functions and numbers, is this question the answer
log(2x + 3y) = log(2x + 3y)
(is this correct)

For 1, you're mostly on the right track, but since you started with ln, you should end with ln. Also, you shouldn't have the business with A/B in there. IOW, it should look like this:
ln (x2 / y2)
= ln x2-ln y2
= 2ln x - 2ln y

You're pretty much done at this point, but this could also be written as 2(ln x - ln y), which is equal to 2 ln(x/y).

For 2, there is nothing you can do with it. There is no property of logarithms that works on a sum of terms.
 

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