Logarithms questions need checking

[JakePearson]

1. ln (x² / y²)
= log (A / B) = logA-logB
= logx²-logy²
= 2logx - 2logy
(is this correct)

2. can this expression be split into separate log functions and numbers, is this question the answer
log(2x + 3y) = log(2x + 3y)
(is this correct)

 

[Bohrok]

What you have in 1. is correct, so you should be able to split, or expand, ln(x²/y²) correctly.
For 2., where did log(2x + 3y) = log(2x + 3y) come from?

 

[Mark44]

1. ln (x² / y²)
= log (A / B) = logA-logB
= logx²-logy²
= 2logx - 2logy
(is this correct)

2. can this expression be split into separate log functions and numbers, is this question the answer
log(2x + 3y) = log(2x + 3y)
(is this correct)

For 1, you're mostly on the right track, but since you started with ln, you should end with ln. Also, you shouldn't have the business with A/B in there. IOW, it should look like this:
ln (x² / y²)
= ln x²-ln y²
= 2ln x - 2ln y

You're pretty much done at this point, but this could also be written as 2(ln x - ln y), which is equal to 2 ln(x/y).

For 2, there is nothing you can do with it. There is no property of logarithms that works on a sum of terms.