Does the limit of y(t) exist for the logistic equation dy/dt = y(0.5 - 0.01y)?

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Homework Statement



A population develops according to logistic equation:
[tex]\frac{dy}{dt} = y(0.5-0.01y)[/tex]

Determine the following:
[tex]\lim_{t\rightarrow\infty} y(t)[/tex]


The Attempt at a Solution



By finding an equilibrium solution to the differential equation, we see that dy/dt = 0 when y = 0 or y = 50.

But does the limit exist? What if y = 0 initially?
 
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But do you have to do the differential to determine the limit? Because we can see that if y=0 and t goes to infinity, y will still equal 0. and if y does not equal 0 initially, then y will go to 50.
 
You have picked two fixed values for y which indeed satisfy the differential equation, however these values aren't the only solutions. The more interesting solutions are the ones that still depend on t.
 
I'm sorry, I don't understand.

I solved the differential equation:

y(t) = 50 / (1+Ae^(-0.5t)

where A = (50-y(0)) / y(0)

so isn't it still dependent on the value of y(0)?
 
Last edited:
OH. so now if we take the limit, as t approaches infinity, then A will go to 0, no matter what. is that correct?
 
ah okay, thanks.

i still don't get the concept though. how can the limit of the equation be 50 if the initial population is 0?
 
Since the equation is modeling the development of a population, that would imply that y(0) cannot be zero; otherwise you have no population to begin with.
 
haha, i suppose. thanks very much cyosis and fightfish.
 
nietzsche said:
OH. so now if we take the limit, as t approaches infinity, then A will go to 0, no matter what. is that correct?
No, it's not. As fightfish said, Ae-.5t goes to 0 as t approaches infinity. This, however, does not imply that A is 0 or is approaching zero. A is a constant in the problem.
 
>> how can the limit of the equation be 50 if the initial population is 0?

You need to object to nietsche, who said the solution is:
y(t) = 50 / (1+Ae^(-0.5t)
that is NOT the solution if y(0)=0...