The system shown below are in equilibrium with m = 4.50 kg. If the spring scale is calibrated in newtons, what does it read? (Ignore the masses of the pulleys and strings, and assume the incline is frictionless.) There is a picture on this question but the best thing I can do is to describe it for you. There are two equal masses on each side of the table supporting by its' pulleys. Each mass is attached to each end of the spring scale. I'm kind of lost on this question. Does the two objects pull the spring scale in both directions, left and right, creating a force of 88.29N (F=2*ma=2*(4.50kg*9.81m/s^2))? Can anyone help me out on this question?