yuiop said:
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I like the idea of the measuring tape as an instrument that measures accumulated distance similar to the way a clock measures accumulated elapsed time. I would add one small correction. The measuring tape reads the current separation according to the stay at home twin.
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The tape measure that I was describing reads the current separation of the twins, at each instant in the traveler's life, ACCORDING TO THE TRAVELER.
But they can EACH have their OWN measuring tape.
The traveler holds the reel-end of HIS tape, with the tip of that tape permanently attached to the home twin. The traveler can read HIS tape to determine their separation, according to HIM, at each instant of HIS life.
The home twin holds the reel-end of HER tape, with the tip of that tape permanently attached to the traveler. The home twin can read HER tape to determine their separation, according to HER, at each instant of HER life.
Note that the above two descriptions of the two tapes are COMPLETELY SYMMETRICAL between the traveler and the home twin. But that symmetry DOESN'T occur in what I'm about to describe.
The point that is frequently missed, about the length contraction result, is this:
Suppose that d_T(t) is the separation of the twins at time t of the TRAVELER'S life, according to HIM.
Then the length contraction result says that d_H(t), which is their separation at time t of the TRAVELER'S life, according to HER, is given by
d_H(t) = gamma * d_T(t) ,
where gamma = 2 in my example. Note that for BOTH distances, the instant in question is time t of the TRAVELER'S life.
For example, take t = 20 years (the time in the traveler's life when he does his instantaneous turnaround).
The traveler says that, since his velocity has been 0.866c for 20 years, that his distance from his twin must be 0.866*20 = 17.32 lightyears.
The home twin says that she was 40 when he was 20 (at the turnaround). So she says he has been moving at 0.866c for 40 years, and therefore their separation must be 0.866*40 = 34.64 lightyears, which agrees with the above equation.
The frequently missed p
oint, is that the above result ISN'T symmetrical between the traveler and the home twin: each of the above distances are the distances at some given instant of the TRAVELER'S life. The equation says that, at some given instant in the traveler's life, the home twin will conclude that their separation is TWICE as great as what the traveler concludes.
There is ANOTHER, DIFFERENT length contraction result, that relates the distances at some given instant of the HOME TWIN'S life. That DIFFERENT equation says that, at some given instant in the HOME TWIN'S life, the home twin will conclude that their separation is HALF as great as what the traveler concludes. I.e., that DIFFERENT equation would be written
D_H(tau) = D_T(tau) / gamma ,
where tau is any given instant in the HOME TWIN'S life. Note that I've use a capital D for the distances in this latter equation, different from the lower-case d that I used in the first equation, because they are different FUNCTIONS, taking a DIFFERENT argument.
For example, take tau = 20 years (the instant in the HOME TWIN'S life when she is 20 years old).
The home twin says that, since the traveler has been moving at 0.866c for 20 years, that his distance from her must be 0.866*20 = 17.32 lightyears.
The traveler says that he was 40 when she was 20. So he says that he has been moving at 0.866c for 40 years, and therefore their separation must be 0.866*40 = 34.64 lightyears, which agrees with the above equation.
The fact that there are TWO DIFFERENT length contraction equations, as described above, is why BOTH the traveler AND the home twin can EACH legitimately and consistently maintain that a moving rod (stationary in the other's frame) is only half as long as the other twin says it is.
Mike Fontenot