Question about "odometer" analogy and time dilation

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SUMMARY

The forum discussion centers around the analogy of an odometer to explain time dilation in the context of special relativity. Participants debate whether two starships, each launching probes after synchronizing their clocks, can determine which ship is moving based on the readings of the probes. It is established that the paths through spacetime for the probes will be symmetric if the ships have identical acceleration profiles, and thus, they will show the same time upon arrival. The discussion emphasizes that the odometer analogy does not imply absolute motion but rather illustrates differential aging in relativity.

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  • #31
phinds said:
The odometer analogy does NOT explain time dilation, it explains differential ageing.
This is incorrect. It explains both if applied correctly.
 
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  • #32
FIL said:
I don't think the video was wrong I probably just misunderstood it.
But this is the point. There are several members here who are qualified to determine whether the video was wrong or if you misunderstood. Both happen frequently.
 
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  • #33
Mister T said:
By symmetrical do you mean simultaneous? Recall that simultaneity is relative. Two events that are simultaneous in the rest frame of one of the ships will not be simultaneous in the rest frame of the other ship.

Edit: By this I mean that if the two launches are simultaneous in the rest frame of one of the ships, they will not be simultaneous in the rest frame of the other ship.
Later in the thread I amended the scenario so that the probe launches occur when the two ships measure an agreed upon distance between themselves after they pass.

After seeing the spacetime diagram Ibix provided I understand it doesn't matter, if motion is regarded as relative the proper time each probe accumulates will always be identical. I was supposing some version of absolute motion without entirely realizing it, I thought it was more of a case of "objectively, there is a true velocity each ship carries with respect to the other, but there's no way to detect it" as opposed to it truly being relative.
 
  • #34
Ibix said:
both at 0.4c. Five minutes later they launch probes, represented by the thinner lines moving at 0.95c. They catch up with the opposite spaceship at 12.27 minutes after the first meeting.
Why were these values chosen?
Of course, they are correct,
and a computer wouldn't have any problem with them,
but the arithmetic seems (in my opinion) unnecessarily complicated to make your point.
A return leg of 0.8c would have been better.
(An outgoing leg of 0.6 would also help simplify the arithmetic.
I have a fondness for 3/5, 4/5, 15/17... https://en.wikipedia.org/wiki/Pythagorean_triple .)
 
  • #35
robphy said:
Why were these values chosen?
0.6c and 0.8c made for a very long chase phase (5 mins to launch, then 30 mins to overtake) and I wanted the diagram to be reasonably wide and short so you can see the ticks clearly. 0.4 and 0.95 were pretty arbitrary, I admit.
 

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