Lorentz Force Part 2: Proving v.E = 0, E.B = 0, v ≥ E/B

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SUMMARY

The discussion focuses on proving three key relationships involving a charged particle P moving with constant velocity v in the presence of uniform electric field E and magnetic field B. It establishes that v.E = 0 and E.B = 0, utilizing the property that the magnetic force is always perpendicular to the velocity of the charge. Additionally, it concludes that the relationship v ≥ E/B holds true, derived from the conditions on the magnitudes of the forces and the angle between them.

PREREQUISITES
  • Understanding of vector algebra, particularly dot and cross products.
  • Familiarity with the concepts of electric and magnetic forces in physics.
  • Knowledge of the principles of motion in inertial frames.
  • Basic understanding of the Lorentz force law.
NEXT STEPS
  • Study the Lorentz force law and its implications on charged particle motion.
  • Learn about vector operations, specifically dot products and cross products in physics.
  • Explore the relationship between electric and magnetic fields in electromagnetic theory.
  • Investigate the conditions for equilibrium in charged particle dynamics.
USEFUL FOR

Students in high school or early college physics courses, educators teaching electromagnetism, and anyone interested in the fundamentals of charged particle dynamics in electric and magnetic fields.

imy786
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Homework Statement



The motion of a charged particle P, observed in an inertial frame S. It is found that P moves with constant velocity v through a region of space where there is a uniform electric field E and a uniform magnetic field B. The speed v = |v|and the field magnitudes E = |E| and B = |B| are all non-vanishing.

Show that v.E =0.

Show that E.B =0.

Show that v ≥ E/B.


dont know how to start this.Need help.
 
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imy786 said:

Homework Statement



The motion of a charged particle P, observed in an inertial frame S. It is found that P moves with constant velocity v through a region of space where there is a uniform electric field E and a uniform magnetic field B. The speed v = |v|and the field magnitudes E = |E| and B = |B| are all non-vanishing.

Show that v.E =0.

Show that E.B =0.

Show that v ≥ E/B.


dont know how to start this.Need help.

As someone told you in the other thread, the first thing to realize is what it means to say that the velocity is constant. What does it imply for the electric and magnetice force?

Then, to answer the first two questions, it is possible to either prove the answers using words only, by talking aboutthe direction of the forces and so on (using the fact that the magnetic force is always perpendicular to the velocity of the charge). Or they can be answered using algebra only and using the obvious identity {\vec A} \cdot ({\vec A} \times {\vec B}) = 0 for any two vectors A and B.
For the third question, just write the condition on the magnitudes of the forces and isolate v. The answer will contain a sin theta and since theta may vary from 0 to 180 degrees, you will find that v \leq E/B as stated.

Btw, this should have been posted in the introductory physics forum, probably.

Regards
 
nrged- thanks for the advice,

so why do you think is introductory level.

What level do you think this is? college/ high school/under/ grad/phd?
 
imy786 said:
nrged- thanks for the advice,

so why do you think is introductory level.

What level do you think this is? college/ high school/under/ grad/phd?
This material is usually covered in high school physics and freshman year of college. Read some of the other advanced level threads for comparison.
 

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