Lorentz Transformation in New Coordinates

Click For Summary

Discussion Overview

The discussion centers on the application of the Lorentz transformation to cylindrical coordinates, specifically transforming from coordinates (r, θ, z) to (r', θ', z') in a frame moving along the z-axis. The participants explore how the transformation equations would adapt from rectangular to cylindrical coordinates.

Discussion Character

  • Exploratory, Technical explanation

Main Points Raised

  • One participant presents the standard Lorentz transformation equations in rectangular coordinates and seeks to adapt them for cylindrical coordinates.
  • Another participant proposes a transformation for a frame moving along the z-axis, suggesting that ct' = γ (ct - βz), r' = r, θ' = θ, and z' = γ (z - βct).
  • A later reply confirms the proposed transformation, noting that if the motion is in the z direction, the x and y coordinates remain unchanged, and the r and θ coordinates are dependent on x and y.
  • There is an expression of understanding and appreciation for the clarification provided in the discussion.

Areas of Agreement / Disagreement

Participants appear to agree on the proposed transformation for the cylindrical coordinates under the specified conditions, with no significant disagreement noted.

Contextual Notes

The discussion does not address potential limitations or assumptions inherent in the transformation process, such as the dependence on the definitions of coordinates or the implications of the transformation in different contexts.

soupdejour
Messages
10
Reaction score
0
I know the Lorentz transformation in rectangular coordinates

<br /> ct&#039; = \gamma (ct - \beta x)<br />
<br /> x&#039; = \gamma (x - \beta ct)<br />
<br /> y&#039; = y<br />
<br /> z&#039; = z<br />

I want to do this same transformation, but from cylindrical coordinates (r,\theta,z) to (r&#039;,\theta&#039;,z&#039;).

Any ideas?
 
Physics news on Phys.org
To make things straightforward, I just want the new frame to be moving along one dimension, say z. My guess is

<br /> ct&#039; = \gamma (ct - \beta z)<br />
<br /> r&#039; = r<br />
<br /> \theta&#039; = \theta<br />
<br /> z&#039; = \gamma (z - \beta ct)<br />
 
soupdejour said:
To make things straightforward, I just want the new frame to be moving along one dimension, say z. My guess is

<br /> ct&#039; = \gamma (ct - \beta z)<br />
<br /> r&#039; = r<br />
<br /> \theta&#039; = \theta<br />
<br /> z&#039; = \gamma (z - \beta ct)<br />

Yes, that is exactly right. If the motion is in the z direction, the x and y coordinates do not change, and the r and θ coordinates depend only on x and y (and vice-versa).
 
DrGreg said:
Yes, that is exactly right. If the motion is in the z direction, the x and y coordinates do not change, and the r and θ coordinates depend only on x and y (and vice-versa).

Awesome, I understand, Thanks!
 

Similar threads

Replies
8
Views
2K
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 101 ·
4
Replies
101
Views
7K
  • · Replies 54 ·
2
Replies
54
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 40 ·
2
Replies
40
Views
6K