Lorentz Transformation: Matrix Relation, Metric Tensor

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SUMMARY

The discussion centers on the properties of Lorentz transformation matrices (denoted as ##\Lambda##) and their relationship with the metric tensor (##\eta##) in flat spacetime. It is established that the Lorentz transformation must satisfy the equations ##\Lambda^{\mu}{}_{\nu '} \Lambda^{\rho}{}_{\sigma '} \eta_{\mu \rho} = \eta_{\nu ' \sigma '}## and ##\Lambda^{\nu '}{}_{\mu} \Lambda^{\sigma '}{}_{\rho} \eta^{\mu \rho} = \eta^{\nu ' \sigma '}##, highlighting the importance of unprimed and primed indices. The metric tensor and its inverse are identical in flat spacetime, which leads to confusion regarding their representation in the equations. The discussion clarifies that while the components of the metric tensor are the same, the indices indicate different coordinate systems.

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TimeRip496
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As known, any Lorentz transformation matrix
##\Lambda##
must obey the relation
##\Lambda^μ{}_v####\Lambda^ρ{}_σ##gμρ=gvσ
. The same holds also for the inverse metric tensor
g
which has the same components as the metric tensor itself (don't really understand why every tex formula starts from a new line), i.e.
##\Lambda^v{}_μ####\Lambda^ρ{}_σ##g=gμρ
. Putting this all as a matrix relation, these two formulas are
ΛTgΛ=g , ΛgΛT=g
, where g is the metric tensor (and also the inverse metric tensor, as they are both the same).

I don't understand why is the lambda transpose and why the two different metric tensor suddenly become the same g. Is there something that I am missing out? And I a bit unsure of the inverse metric tensor stated above.
 
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TimeRip496 said:
I don't understand why is the lambda transpose and why the two different metric tensor suddenly become the same g.

A Lorentz transformation transforms between different inertial coordinate systems in flat spacetime. The metric tensor of flat spacetime is the same as the inverse metric tensor--i.e., the numerical values of the components are the same.

As for the transpose of the Lambda matrices, I'm not sure you have that right, because your Lorentz transformation matrices should have one unprimed and one primed index (unprimed for one frame, primed for the other), and the two expressions for the metric should also differ similarly. Using the standard symbol ##\eta## for the metric of flat spacetime, the relationships you wrote down would be:

$$
\Lambda^{\mu}{}_{\nu '} \Lambda^{\rho}{}_{\sigma '} \eta_{\mu \rho} = \eta_{\nu ' \sigma '}
$$

$$
\Lambda^{\nu '}{}_{\mu} \Lambda^{\sigma '}{}_{\rho} \eta^{\mu \rho} = \eta^{\nu ' \sigma '}
$$

Notice the primed and unprimed indices and how they are exchanged between the first and second equations. Also note that, although the ##\eta## matrices are all the same, in the sense that each individual component is the same, the equations refer to different components because of the different indices, so they are not saying the same thing.
 

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