Lost on Word Problem Homework: Min Cost of Storing Units

  • Thread starter Thread starter willywonka12345
  • Start date Start date
  • Tags Tags
    Lost Word problem
Click For Summary

Homework Help Overview

The problem involves determining the minimum cost associated with storing a product, represented by the quadratic function C(x) = 0.8x^2 - 12.8x + 2600, where C is in dollars and x is in hundreds of units. The original poster expresses uncertainty about how to approach the problem and seeks assistance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods to find the minimum cost, including graphing the function and using derivatives. Some suggest completing the square as an alternative approach. There are questions about the correctness of calculations and interpretations of the function's behavior.

Discussion Status

The discussion is active, with participants exploring different methods to analyze the cost function. Some guidance has been provided regarding completing the square, and there is a recognition of the minimum cost's relationship to the vertex of the quadratic function. However, there is no explicit consensus on the final answer.

Contextual Notes

Participants mention limitations in their current knowledge, particularly regarding derivatives, which may affect their ability to fully engage with the problem. The original poster has a deadline approaching for submitting their homework.

willywonka12345
Messages
15
Reaction score
0

Homework Statement



The cost associated with storing x units of a certain product is given by the function C(x) = 0.8x^2 - 12.8x + 2600 where C is measured in dollars and x in hundreds of units. What is the minimum cost ?

The Attempt at a Solution



Umm, yea. I would attempt it but I have no idea where to start, but I will try anyways. So I was thinking it needs to be set up ( y = mx + b ) so I did and got a final result of : y = square root of 16x - 3250 OR : y = (16x - 3250)^.5

I then plotted it on a graph and figured that I need to find minimum x for some reason because y didn't make much sense as it came to be 0. So then the minimum x was about 204 on the graph when y = 0. So I was thinking that is my answer but have absolutely NO clue ! :smile: Please help me !
 
Physics news on Phys.org
Do you have any knowledge of derivatives.Please tell me if i can help...it wud be great if i could help ...i myslef have only limited knowledge.However...C(x) = 0.8x^2 - 12.8x + 2600 is the equation we have.Now if we take y=c(x)

and differentiate it with respect to x...i think you would get ur answer setting \frac {dy}{dx}=0
 
No clue, we haven't got that far into the book. So that would tell me that it wouldn't be necessary to use that. But as before, still not sure. I wish you could help, I have a couple days to get the answer before returning to school so hopefully someone will know.
 
Hm...i gues ud have to graph the equation y=C(x)= 0.8x^2 - 12.8x + 2600 !
 
And then what. lol
 
find the curves minima point.I mean where the slope is 0!.
 
Which would be 2600. Surely that's not right.
 
No, the slope is not zero at when C(x)=2600! Look harder.
 
and that's one of my weaknesses. So after looking at it again harder, I am getting something like x is around 8 and y is around 2548 but still am not sure as to what my answer is. 2548 dollars ?
 
Last edited:
  • #10
If you want to do this without using derivatives and without using a graph, complete the square in the expression for C(x). Ie write it in the form:

C(x)=0.8*(x-A)^2+B

(Where you have to figure out what A and B are). Then clearly the minimum is where x=A and it's value is?
 
  • #11
Ahhhhhhhhh, that is what I am talking about. Didn't think of the standard form dealio. Thanks Dick.

So C(x) = 0.8(x-6.4)^2 + 2559.04 , so the minimum you are saying would be 6.4 or 2559.04. I am thinking you are saying it is 6.4 because I believe you take the opposite sign of A in the (). Correct ? 6.4 ?
 
  • #12
The value of x at which the minimum occurs is x=6.4. At x=6.4 the cost C(x) reaches a minimum value of 2559.04. The question asks for minimum cost. (I'm trusting you got the numbers right - I didn't check them).
 
  • #13
No. You didn't get the numbers right. Multiply your C(x) back out. Do you get back to the original?
 
  • #14
I didn't divide the .8 into 12.8. This one comes out right :

C(x) = 0.8(x-8)^2 + 2536 and then you kinda lost me as to finding the minimum cost.
 
  • #15
The squared term is always greater than or equal to zero. So the x value where it is zero defines the minimum of C(x). C(8)=2536 is the minimum cost. That's pretty close to what you were seeing on your graph.
 
  • #16
Excellent, thanks so much for the help Dick. I like your way a whole lot better than the graph way !
 
  • #17
Glad you like it. Wait till you get to derivatives. You'll LOVE them.
 
  • #18
Dick said:
Glad you like it. Wait till you get to derivatives. You'll LOVE them.



I lol'ed.

@OP:
Your textbook may have it listed as "completing the square", in case you were interested.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
4K
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 43 ·
2
Replies
43
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K